Sigma and Pi Bonds for Diatomic Oxygen Molecule

In summary, according to the Molecular orbital theory, diatomic oxygen has three "bonds" and one set of unpaired electrons, with the unpaired electrons being in antibonding orbitals. This results in a bond order of 2, which is different from the double bond described by the valence bond theory. It was shown in 1937 that VB theory predicts the same ground state as MO theory, and the paramagnetic properties of oxygen support this. The pi bonds in oxygen are considered "half" bonds, with a bond order of 1/2.
  • #1
Conservation
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According to the Molecular orbital theory, diatomic oxygen should have σ2px (internuclear axis) and [itex]\pi[/itex]2py and [itex]\pi[/itex]2pz orbitals filled with two unpaired electrons, one at antibonding [itex]\pi[/itex]2py and the other at antibonding [itex]\pi[/itex]2pz. And of course, the 2s bonding and antibonding orbitals as well.
According to the molecular orbital theory, does this imply that diatomic oxygen possesses three "bonds" and one set of unpaired electrons, opposed to the double bond (sigma pi) implied by the valence bond theory?

Thank you.
 
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  • #2
The unpaired electrons are in fact antibonding, so that the bond order is 3-2x1/2=2.
In contrast to folk expositions of VB theory, VB theory predicts the same ground state as MO theory and not two double bonds, which rather describes bonding in the excited singulet oxygen.
This was shown already in 1937 by Wheland and Lennard-Jones:
http://pubs.rsc.org/en/content/articlelanding/1937/tf/tf9373301499#!divAbstract
 
  • #3
Right, hence the paramagnetic properties displayed in oxygen to point out the flaws of VB theory.

However, if the two unpaired electrons are antibonding, does that make the π2py and π2pz bonds "half" bonds? So one "full" sigma bonds at x and two "half" bonds at y and z planes to add up to two?
 
  • #4
Conservation said:
Right, hence the paramagnetic properties displayed in oxygen to point out the flaws of VB theory.

As I tried to explain, VB gives a correct description of bonding in oxygen, so it is not flawed.
Furthermore, also the singlet state of oxygen is about as paramagnetic as the triplet state, due to orbital momentum, so oxygen being paramagnetic does not help to decide whether the ground state is singlet or triplet.

However, if the two unpaired electrons are antibonding, does that make the π2py and π2pz bonds "half" bonds? So one "full" sigma bonds at x and two "half" bonds at y and z planes to add up to two?
Yes, the pi bonds both have a bond order of 1/2.
 
  • #5


I would like to clarify that the concept of "bonds" in molecular orbital theory is different from that in valence bond theory. In molecular orbital theory, the concept of bonds is based on the idea of electron sharing between atoms, rather than the overlapping of atomic orbitals as in valence bond theory.

In the case of diatomic oxygen, the molecular orbital theory predicts the presence of three "bonds" - two sigma bonds and one pi bond. However, these bonds are not localized between two specific atoms, as in valence bond theory. Instead, they are spread out over the entire molecule and involve the sharing of electrons between all the atoms in the molecule.

Furthermore, the presence of unpaired electrons in certain antibonding orbitals does not necessarily imply the existence of additional bonds. These electrons are actually destabilizing the molecule and make it more reactive. Therefore, we cannot equate the number of unpaired electrons with the number of bonds in molecular orbital theory.

Overall, the concept of bonds in molecular orbital theory is more complex and involves a more holistic understanding of the electronic structure of molecules. It cannot be directly compared to the simpler concept of bonds in valence bond theory.
 

1. What are sigma and pi bonds?

Sigma and pi bonds are types of covalent bonds that form between atoms when they share electrons. Sigma bonds are formed when electrons are shared in an overlapping head-to-head fashion, while pi bonds are formed when electrons are shared in an overlapping side-to-side fashion.

2. How many sigma and pi bonds are present in a diatomic oxygen molecule?

A diatomic oxygen molecule (O2) has one sigma bond and two pi bonds. The sigma bond is formed by the overlap of the two atomic orbitals, while the two pi bonds are formed by the overlap of the two unhybridized p-orbitals.

3. How do sigma and pi bonds contribute to the stability of the diatomic oxygen molecule?

The sigma and pi bonds in a diatomic oxygen molecule contribute to its stability by holding the two oxygen atoms together. The overlapping of their atomic orbitals allows for the formation of a strong bond between the atoms, making it difficult to break them apart.

4. Are sigma and pi bonds equally strong?

No, sigma bonds are generally stronger than pi bonds. This is because the head-to-head overlap of atomic orbitals in sigma bonds allows for a greater degree of electron sharing, resulting in a stronger bond. Pi bonds, on the other hand, have a weaker side-to-side overlap and are therefore not as strong.

5. Can sigma and pi bonds be found in other molecules besides diatomic oxygen?

Yes, sigma and pi bonds can be found in many different molecules. Sigma bonds can form between any two atoms that are connected by a single bond, while pi bonds can form between atoms that are connected by a double or triple bond. These bonds play a crucial role in the formation and stability of many different types of molecules.

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