Intensity of stokes and anti-stokes lines?

In summary, the Raman effect shows that intensity is directly proportional to the 4th power of the wavelength. However, stokes lines, which have higher wavelengths, are more intense than anti-stokes lines due to the population distribution of different vibrational levels at thermal equilibrium. At low temperatures, the Bose occupation number causes significant differences in the populations of these levels. This explains why stokes transitions are more probable than anti-stokes transitions.
  • #1
itari1985
4
0
According to Raman effect, the intensity is directly proportional to the 4th power of the wavelength. Then how come stokes lines, which have higher wavelengths than anti-stokes lines, are more intense than the anti-stokes lines?
 
Physics news on Phys.org
  • #2
uh? I think you answered your own question. If I is propotional to lambda to power 4 and the stokes line has higher wavelengths of course they're more intense then.
 
  • #3
If I remember well, the anti-stokes line is near absorption bands. Its gain is too low there, so it is less intense than stokes line.
 
  • #4
Sorry intensity is inversely proportional to the 4th power of wavelength.:biggrin:
 
  • #5
Isn't the lambda^-4 dependence characteristic of Rayleigh scattering?

Claude.
 
  • #6
To have a Raman anti-stoke diffusion, we need to have a transition of an atom initially in a excited vibrationnal level to the ground level (if we forget the intermediate virtual state). The stoke diffusion, instead, relies on a transition from the ground level to an excited vibrationnal level.

At thermal equilibrium, the populations of the different levels follows the Boltzmann distribution. So the population of the ground level is higher that the excited level. So the stokes transition is much more probable that the anti-stokes transition.

Does it answer to the question ?

Barth
 
  • #7
To add a touch to Claude's and Barth's posts : vibrational eigenmodes (or phonons in solids) are bosons. Their distribution among different levels is given by the Bose occupation number. At low temperatures, the different levels have significantly different populations.
 
Last edited:
  • #8
yes it does answer my question. Thanx
 

1. What is the difference between stokes and anti-stokes lines in intensity?

Stokes lines are produced when a molecule absorbs a photon, causing it to go from a lower energy state to a higher energy state. Anti-stokes lines are produced when a molecule emits a photon, causing it to go from a higher energy state to a lower energy state. The intensity of stokes lines is typically higher than that of anti-stokes lines due to the higher probability of absorption compared to emission.

2. How does the intensity of stokes and anti-stokes lines change with temperature?

The intensity of both stokes and anti-stokes lines increases with temperature due to the increased thermal energy of the molecules. However, the intensity of anti-stokes lines typically increases at a faster rate due to the higher probability of molecules being in higher energy states at higher temperatures.

3. What factors affect the intensity of stokes and anti-stokes lines?

The intensity of stokes and anti-stokes lines is affected by several factors, including the concentration of molecules, the temperature, and the energy of the incident photons. Additionally, the selection rules for a particular molecule and the polarization of the incident light can also affect the intensity of these lines.

4. How are stokes and anti-stokes lines used in spectroscopy?

Stokes and anti-stokes lines are used in spectroscopy to determine the energy levels and transitions of molecules. By measuring the intensity of these lines at different temperatures and concentrations, researchers can gather information about the molecular structure and interactions. Additionally, the ratio of stokes to anti-stokes intensities can provide information about the temperature of a system.

5. Can the intensity of stokes and anti-stokes lines be manipulated?

Yes, the intensity of stokes and anti-stokes lines can be manipulated by changing the experimental conditions, such as the temperature and concentration of molecules, or by using different incident light sources with varying energies and polarizations. This allows for more precise measurements and control in spectroscopic studies.

Similar threads

  • Atomic and Condensed Matter
Replies
2
Views
2K
  • Introductory Physics Homework Help
Replies
1
Views
1K
  • Atomic and Condensed Matter
Replies
2
Views
4K
  • Advanced Physics Homework Help
Replies
3
Views
2K
  • Atomic and Condensed Matter
Replies
6
Views
3K
  • Atomic and Condensed Matter
Replies
1
Views
3K
  • Calculus and Beyond Homework Help
Replies
6
Views
2K
  • Differential Equations
Replies
2
Views
1K
Replies
3
Views
1K
  • Introductory Physics Homework Help
Replies
6
Views
3K
Back
Top