Done by parts integral and simplify

In summary, a "done by parts" integral is a method used to evaluate integrals that cannot be solved by other techniques, such as substitution or the power rule. It involves using the product rule of derivatives to break down the integral into smaller, more manageable parts. The part that is integrated is typically the part that becomes simpler after each integration, while the part that is differentiated is typically the part that becomes more complicated after each differentiation. This method is best used when the integral involves a product of two functions or a function raised to a power, and there is no other applicable method. The general formula for solving "done by parts" integrals is ∫u*dv = uv - ∫v*du. An example of solving
  • #1
Yegor
147
1
i have to integrate the next:

(x^2)(e^x)dx/((x+2)^2)

It should be done by parts.
How I can simplify it?

Is (4x+4) (e^x) dx/(x+2)^2 easier to be integrated?
 
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  • #2
the easiest way to do this is by parts.
let u=(x^2)(e^x)
let dv = 1/(x+2)^2

get du by differentiating u by x
get v by integrating dv in terms of x

then write out u*v - integral(v*du)
the integral simplifies pretty nicely.
 
  • #3
Thank You a lot!
 

1. What is a "done by parts" integral?

A "done by parts" integral is a method used to evaluate integrals that cannot be solved by other techniques, such as substitution or the power rule. It involves using the product rule of derivatives to break down the integral into smaller, more manageable parts.

2. How do you determine which part to integrate and which part to differentiate in the "done by parts" method?

In the "done by parts" method, the part that is integrated is typically the part that becomes simpler after each integration, while the part that is differentiated is typically the part that becomes more complicated after each differentiation. This allows for the integral to eventually be solved.

3. When should I use the "done by parts" method?

The "done by parts" method is best used when the integral involves a product of two functions, and neither substitution nor the power rule can be applied. It can also be used when the integral involves a function raised to a power, such as x2 or sin(x).

4. Can you provide an example of solving an integral using the "done by parts" method?

Sure, an example would be solving ∫x*sin(x)dx. Using the "done by parts" method, we would let u = x and dv = sin(x)dx. This means du = dx and v = -cos(x). Plugging these into the integral formula, we get ∫x*sin(x)dx = -x*cos(x) + ∫cos(x)dx. This integral can now be solved using substitution or the power rule.

5. Is there a general formula for solving "done by parts" integrals?

Yes, the general formula for "done by parts" integrals is ∫u*dv = uv - ∫v*du. This formula can be used to evaluate any integral that can be solved using the "done by parts" method.

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