- #1
granpa
- 2,268
- 7
is this true?
http://en.wikipedia.org/wiki/Impedance_mismatch
To prevent all reflections of the signal back into the source, the load (which must be totally resistive) must be matched exactly to the source impedance (which again must be totally resistive)
what if you divide the wire into 2 parts. isn't the impedance of each complex? so shouldn't there be reflection at the boundary? obviously that makes no sense. what am i missing.
http://en.wikipedia.org/wiki/Impedance_mismatch
To prevent all reflections of the signal back into the source, the load (which must be totally resistive) must be matched exactly to the source impedance (which again must be totally resistive)
what if you divide the wire into 2 parts. isn't the impedance of each complex? so shouldn't there be reflection at the boundary? obviously that makes no sense. what am i missing.