- #1
Dell
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given the integral
[tex]\int[/tex]e[tex]\sqrt[3]{x}[/tex]dx from 8 to 27
i called [tex]\sqrt[3]{x}[/tex]=t
and integrate now from 2-3
x=t3
dx=3t2dt
[tex]\int[/tex]et3t2dt
=3[tex]\int[/tex]ett2dt
u=t2
du=2tdt
dv=etdt
v=et
[tex]\int[/tex]udv=uv-[tex]\int[/tex]vdu
3[tex]\int[/tex]ett2dt=3(t2et-[tex]\int[/tex]et2tdt)
is this correct so far?? do i now need to, again integrate in parts, now
u=t
du=dt
dv=etdt
v=et
?
[tex]\int[/tex]e[tex]\sqrt[3]{x}[/tex]dx from 8 to 27
i called [tex]\sqrt[3]{x}[/tex]=t
and integrate now from 2-3
x=t3
dx=3t2dt
[tex]\int[/tex]et3t2dt
=3[tex]\int[/tex]ett2dt
u=t2
du=2tdt
dv=etdt
v=et
[tex]\int[/tex]udv=uv-[tex]\int[/tex]vdu
3[tex]\int[/tex]ett2dt=3(t2et-[tex]\int[/tex]et2tdt)
is this correct so far?? do i now need to, again integrate in parts, now
u=t
du=dt
dv=etdt
v=et
?
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