- #1
ymehuuh
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Homework Statement
A 81-g ice cube at 0°C is placed in 878 g of water at 25°C. What is the final temperature of the mixture?
Homework Equations
No heat is loss therefore m*Cp*deltaT+m*Cp*deltaT=0
Cp ice=2.09
Cp water=4.19
The Attempt at a Solution
878*4.19*(Tf-25)+81*2.09*(Tf-0)=0
3678.82Tf+169.29Tf=91970.5
Tf=23.9C
The answer is wrong...don't know why...