mathman said:The horizontal and vertical components aren't supposed to be added numerically. Use Pythagorean theorem to get the total, which is the 10 you started with.
mathman said:Doing it in two steps is different. Extreme example - start it horizontally at 100 m/sec, then reverse it with force to make it stop. You will have exerted lots of force, but the projectile will have stopped moving.
V0ODO0CH1LD said:If I throw something at a 30° angle with a velocity of 10m/s, the vertical component is 5m/s and the horizontal component is 5√3 m/s, which equals 8.66 approximately.
Where did the force to get the body those additional 3.66 m/s come from? I mean, I did only input a force to get the object to 10m/s...
A projectile at an angle refers to an object that is launched or thrown at a specific angle with respect to the horizontal plane.
The sum of vectors in a projectile at an angle is the combination of the horizontal and vertical components of the object's velocity. This determines the total speed and direction of the projectile's motion.
The horizontal component can be calculated using the formula Vx = V * cosθ, where V is the initial velocity and θ is the launch angle. The vertical component can be calculated using Vy = V * sinθ, where V is the initial velocity and θ is the launch angle.
The maximum height reached by a projectile at an angle is determined by the vertical component of its velocity. It is equal to Vy^2/2g, where Vy is the vertical component of the initial velocity and g is the acceleration due to gravity.
Air resistance can affect a projectile at an angle by slowing down its horizontal and vertical speed. This results in a shorter range and a lower maximum height reached by the projectile. However, the effect of air resistance is typically small for objects with a high initial velocity or a short flight time.