Induced charge between/above infinite charged plates

In summary, the problem involves two thin plates with total surface charge densities of \sigma and \sigma_{1}, an uncharged conducting slab placed in between them, and then outside \sigma. The question is what are the induced charge densities on the surfaces of the conducting slab in each configuration. The problem also states that the polarities of the charges are not specified and should be treated algebraically. In the first configuration, the neutral surface will have opposite charge densities of -\sigma and -\sigma_{1} in order to create a potential flow. In the second configuration, the neutral surface will only have a partial charge from the nearest plate, which is \sigma. The treatment of polarities algebraically is key in solving this problem
  • #1
mitleid
56
1
No numbers here - purely conceptual.

Two thin plates carry total surface charge densities of [tex]\sigma[/tex] and [tex]\sigma_{1}[/tex] respectively. An uncharged conducting slab is placed in between the charged plates, and then outside [tex]\sigma[/tex]. What are the induced charged densities on the surfaces of the conducting slab in each of the configurations?

The problem also states that 'polarities of those charges ([tex]\sigma[/tex]) are not specified and should be treated algebraically'.

Every example I can find using infinite parallel plates has to do with opposite charged densities. However, this problem does not denote opposite charges of the plates, so... I'm assuming the algebraic note above solves this issue.

For the first configuration (in between), since each of these plates is charged it will induce the opposite charge on the conductive surface in order to create a potential flow (though that part isn't important in this question). So my first guess is the charge densities on the -neutral- surface will become -[tex]\sigma[/tex] and -[tex]\sigma_{1}[/tex].

When it is placed outside the plates the neutral surface will only take on a partial charge from the nearest plate (which is actually [tex]\sigma[/tex]).

But of an odd question that could use some extra commentary.
 
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  • #2
Ah, so... apparently I'm not sure how to treat the polarities algebraically... which is key here I think.
 
  • #3


I would approach this problem by first clarifying the given information and assumptions. The problem states that the plates carry total surface charge densities of \sigma and \sigma_{1}, but does not specify the polarity of these charges. Therefore, I would assume that both plates have the same polarity and treat them algebraically as \pm\sigma and \pm\sigma_{1}.

In the first configuration, the conducting slab is placed in between the charged plates. This will result in induced charges on the surfaces of the slab in order to maintain the electric field equilibrium between the plates. Since the plates have opposite charges, the induced charges on the conductive surface will also be opposite, resulting in -\sigma and -\sigma_{1}.

In the second configuration, the conducting slab is placed outside the plates. In this case, the neutral surface will only experience a partial charge from the nearest plate, which is \sigma. This is because the electric field from the other plate is cancelled out by the conducting slab. Therefore, the induced charge on the surface of the slab will be -\sigma.

It is worth noting that this problem assumes an idealized scenario with infinite parallel plates, which is not possible in reality. In a real-world situation, the induced charges may also depend on the distance between the plates and the conducting slab, as well as the shape and material properties of the plates and the slab.

Overall, the concept of induced charges between and above infinite charged plates is important in understanding the behavior of electric fields and how they interact with conductive materials. It is a fundamental concept in electromagnetism and has many practical applications in various fields of science and technology.
 

1. How is induced charge created between two infinite charged plates?

Induced charge is created between two infinite charged plates when an external electric field is applied to the system. This external field causes the charges on the plates to redistribute, resulting in a separation of positive and negative charges.

2. What is the direction of the induced charge between two infinite charged plates?

The direction of the induced charge is always opposite to the direction of the external electric field. This means that if the external field is pointing towards one plate, the induced charge on that plate will be in the opposite direction.

3. How does the distance between the plates affect the magnitude of the induced charge?

The magnitude of the induced charge is directly proportional to the distance between the plates. This means that as the distance between the plates increases, the magnitude of the induced charge decreases.

4. Can the induced charge between two infinite charged plates be controlled?

Yes, the induced charge can be controlled by changing the strength of the external electric field. By increasing or decreasing the strength of the field, the magnitude and direction of the induced charge can be altered.

5. What is the significance of studying induced charge between infinite charged plates?

The study of induced charge between infinite charged plates is important in understanding the behavior of electric fields and the concept of capacitance. It also has practical applications in devices such as capacitors, which use induced charge to store electric energy.

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