Need help with this heat capacity/ideal gas problem.

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In summary, the conversation discusses the equation Cv/R = A+BT+CT^2 for ideal gases at low densities and pressures. The first question raises the issue of how a gas can be both ideal and follow this equation at the same time. The second question involves finding the final temperature of a gas after expanding in an insulated piston, and the incorrect equation provided is (T2/T1) = (V1/V2)^(R/Cv) = (1/2)^(R/Cv) where Cv is evaluated at T1. The correct equation for solving for T2 is not provided, but it is suggested to find the derivation of the given equation and modify it to include the necessary information about heat capacity.
  • #1
blehxpo
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For many gases at low densities and pressures (where ideal gas behavior is obtained), Cv/R = A+BT+CT^2 where A, B, C, are all constants, with appropriate temperature units so that the RHS (right hand side) of this equation is dimensionless.

a> How can a gas be both ideal and follow the equation above, at the same time.

b> Such a gas initially at T1 expands slowly in an insulated piston to double its original volume you would like to find the final temperature T2. A friend suggest you may use the follow equation that we derived in class:

(T2/T1) = (V1/V2)^(R/Cv) = (1/2)^(R/Cv)

where Cv is evaluated at T1. What is wrong with your friend's statement? Find the correct equation that should be solved (implicitly) to find T2.


Attempt:
a. I said it has to be at constant V and high temperature. Not what it was asking
b. It said it was an insulated piston? Doesnt that mean that T1=T2?? But I have really no idea how to do it. :/

Thanks for the Helps please.
 
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  • #2
For (a), it's an ambiguous question, and I'm not exactly sure what kind of answer they want, but the constant volume thing is definitely wrong because an ideal gas is defined by it's equation of state, which includes how the state variables change with volume. It is also unnecessary, since a gas following this equation could be ideal even as volume changes and with temperature not being high.

For (b), an insulated piston will change it's temperature when work is done on it because of the 1st law. Energy needs to be conserved, so when work is done on the gas and heat can't escape, it's temperature increases, so T2 does not equal T1.

To get the right answer to (b), find where the equation they want to use was derived. Then repeat the derivation, but using what you know about the heat capacity in the necessary place.
 

1. What is heat capacity and why is it important in thermodynamics?

Heat capacity is a measure of the amount of heat required to raise the temperature of a substance by a certain amount. In thermodynamics, it is an important property as it helps us understand how energy is transferred and stored in different materials.

2. What is an ideal gas and how does it behave?

An ideal gas is a theoretical gas that follows the gas laws perfectly at all temperatures and pressures. It is composed of particles that have no volume and do not interact with each other. In other words, it behaves according to the ideal gas law, which states that the pressure, volume, and temperature of an ideal gas are directly proportional to each other.

3. How do you calculate the heat capacity of an ideal gas?

The heat capacity of an ideal gas can be calculated using the formula C = (nR)/2, where C is the heat capacity, n is the number of moles of gas, and R is the gas constant. This formula is valid for both constant volume and constant pressure processes.

4. Can the heat capacity of an ideal gas change with temperature?

No, the heat capacity of an ideal gas is constant and does not change with temperature. This is because an ideal gas does not have any internal energy, so the heat capacity cannot be affected by changes in temperature.

5. How does the heat capacity of an ideal gas compare to that of other substances?

The heat capacity of an ideal gas is relatively low compared to other substances such as liquids and solids. This is because ideal gases have fewer particles and do not have any internal energy, so they require less energy to raise their temperature by a certain amount.

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