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zorro
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Homework Statement
If (1+x+x2+x3)5 = Σk=0k=15akxk, then Σk=0k=7a2k is equal to?
The Attempt at a Solution
Put x=1 in the expression given. We get
45 = a0 + a1 + a2 + ... a15
Put x=-1 in the same expression
0 = a0 - a1 + a2 ... -a15
Adding the two results,
45 = 2(a0 + a2...a14)
So Σk=0k=7a2k = 44 = 256.
The answer given is 512. Can somebody point out my mistake?