Principles of projectile motion and kinematics homework

[tjbateh]

Homework Statement

You throw a ball toward a wall at speed 32.0 m/s and at angle θ0 = 38.0° above the horizontal (Fig. 4-35). The wall is distance d = 15.0 m from the release point of the ball. (a) How far above the release point does the ball hit the wall? What are the (b) horizontal and (c) vertical components of its velocity as it hits the wall?

Homework Equations

The Attempt at a Solution

For part B, I got 25.22 m/s..
When I put in part C as 19.7, which is what i thought it was, it said it's wrong.
What should I do from here?

 

[Doc Al]

While the horizontal velocity remains constant, the vertical velocity changes as the ball moves. You need to know what time the ball hits the wall in order to find the vertical component of velocity.

Solve the problem step by step using the principles of projectile motion and kinematics.

 

[tomcue]

I would first review the principles of projectile motion and kinematics to ensure that I have a solid understanding of the concepts involved in this problem. Projectile motion refers to the motion of an object that is launched into the air and moves along a curved path due to the force of gravity. Kinematics, on the other hand, is the study of the motion of objects without considering the forces that cause the motion.

In this homework problem, we are dealing with a projectile motion where a ball is thrown towards a wall at a certain speed and angle. The goal is to determine the height at which the ball hits the wall and the components of its velocity at that point.

To solve this problem, we can use the equations of projectile motion, which include the equations for horizontal and vertical displacement, velocity, and acceleration. We can also use trigonometric functions to determine the components of velocity.

For part (a), we can use the formula for horizontal displacement, which is given by x = v*cos(θ)*t, where v is the initial velocity, θ is the angle of launch, and t is the time. In this case, we know the initial velocity (32.0 m/s), the angle (38.0°), and the distance to the wall (15.0 m). We can rearrange the equation to solve for time (t) and then plug in the values to get the horizontal displacement, which is the distance above the release point where the ball hits the wall.

For parts (b) and (c), we can use the components of velocity at any given point, which are given by v_x = v*cos(θ) and v_y = v*sin(θ), where v is the velocity and θ is the angle of launch. In this case, we know the initial velocity (32.0 m/s) and the angle (38.0°). We can plug in these values to get the horizontal and vertical components of velocity at the point of impact.

If the answer for part (c) is incorrect, I would double-check my calculations and make sure I am using the correct units. I would also review the principles of projectile motion and kinematics to ensure that I am applying the correct equations and concepts. If I am still unable to determine the correct answer, I would seek help from a classmate, teacher, or tutor to discuss and work through the problem together. It is important to approach homework problems with a