Design an active filter 2nd order

In summary, the filter must have a frequency response as close as possible to the ideal filter response, signals of frequency 0 ~ 5 KHz are only allowed to pass through the filter with a desired gain of 4dB, and capacitor of 0.01uF must use in the active filter design due to its high availability.
  • #1
funjoke88
3
0
• No ripple can exist in the output, but non-linear phase shift is allowed.
• The frequency response must be as close as possible to the ideal filter response.
• Signals of frequency 0 ~ 5 KHz are only allowed to pass through the filter with a desired gain of 4dB . Other frequencies should reduce at least 100 times of gain for every 10 times of frequency increase.
• Capacitor of 0.01uF must use in the active filter design due to its high availability in the stock.
• Minimize offset error of your design


how to determine it and i don't know how to start it ?
 
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  • #2
funjoke88 said:
• No ripple can exist in the output, but non-linear phase shift is allowed.
• The frequency response must be as close as possible to the ideal filter response.
• Signals of frequency 0 ~ 5 KHz are only allowed to pass through the filter with a desired gain of 4dB . Other frequencies should reduce at least 100 times of gain for every 10 times of frequency increase.
• Capacitor of 0.01uF must use in the active filter design due to its high availability in the stock.
• Minimize offset error of your design


how to determine it and i don't know how to start it ?

Start by listing the various choices for filter polynomial type. What are the characteristics of each? Which one(s) have ripple in the passband? Which one(s) don't?

Then look at the attenuation you need to have ("100 times for every 10 times frequency increase") -- what order filter are we talking about now? Is it a LPF, BPF or HPF?

Given all that information, start to sketch out ways to do the active filter... Show us your work.
 
  • #3
Do you have access to a filter design handbook?
 
  • #4
no ripple means butterworth, 4 db means this is HPF

fc=1/2pie RC=7957OHM
Apb =4
20logApb=4
Apb-1.585

Rf=Rapb=7957 x 1.585 =12.6kohm

Apb=1+Rf/Rs
1.585=1/(12.6k/Rs)
Rs=21.54kohm


i just know this few steps .if there any mistake
 

1. What is an active filter 2nd order?

An active filter 2nd order is a type of electronic circuit that is designed to filter out specific frequencies from an input signal. It uses active components such as transistors or operational amplifiers to amplify and shape the output signal.

2. What is the difference between an active filter 2nd order and a passive filter?

The main difference between an active filter 2nd order and a passive filter is that active filters require a power source to operate, while passive filters do not. Active filters also have the ability to amplify the output signal, whereas passive filters can only attenuate the signal.

3. What are the advantages of using an active filter 2nd order?

Some advantages of using an active filter 2nd order include higher gain, better frequency response, and the ability to reduce noise and distortion in the output signal. Additionally, active filters can be designed to have adjustable cutoff frequencies, making them more versatile in different applications.

4. How do I design an active filter 2nd order?

To design an active filter 2nd order, you will need to have a good understanding of circuit analysis and design principles. You will also need to determine the desired specifications for your filter, such as the cutoff frequency and required gain. From there, you can select the appropriate active components and use mathematical equations and circuit simulations to design the filter.

5. What are some common applications of active filter 2nd order?

Active filter 2nd order circuits are commonly used in audio and communication systems to filter out unwanted noise and frequencies. They are also used in power supplies to remove ripple and improve efficiency. Other applications include instrumentation, medical equipment, and control systems.

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