- #1
RedBarchetta
- 50
- 1
Homework Statement
[tex]
\int {\frac{{\cos ydy}}
{{\sin ^2 y + \sin y - 6}} }
[/tex]
The Attempt at a Solution
[tex]
\int {\frac{{\cos ydy}}
{{\sin ^2 y + \sin y - 6}} = } \int {\frac{{\cos ydy}}
{{(\sin y - 2)(\sin y + 3)}}}
[/tex]
Now I attempt to split this into partial fractions:
[tex]
\begin{gathered}
\frac{{\cos y}}
{{(\sin y - 2)(\sin y + 3)}} = \frac{A}
{{\sin y - 2}} + \frac{B}
{{\sin y + 3}} \hfill \\
\cos y = A(\sin y + 3) + B(\sin y - 2) \hfill \\
\cos y = A\sin y + 3A + B\sin y - 2B \hfill \\
\cos y = (A + B)\sin y + 3A - 2B \hfill \\
\end{gathered}
[/tex]
...from here I'm not sure what to do to solve for the coefficients. I can't see any trig identities that would help either. How would you solve for these?
Thank you.