The normal force is one of the forces acting on the block, but it does not equal the weight.queenspublic said:What forces act on the block?
Would that be normal force which is the weight? (40.67? Am I right?)
No. If the weight were equal and opposite to the normal force, the block would just sit there.queenspublic said:My diagram has the normal force that keeps it up. The weight force pulling it down which opposite of normal force.
Tension from what?And tension moving it forward.
OK, that's the net force acting on the block.queenspublic said:Okay...so I used the m*g*sin30
Wrong answer for what?m = 4.15
g = 9.8
and I still got the wrong answer.
If you want to find the acceleration, divide the net force by the mass. (F = ma → a = F/m.)then i divided by mass again and got wrong answer again.
The magnitude of acceleration of a block refers to the rate of change of its velocity over time. It is a measure of how quickly the block's speed or direction is changing.
The magnitude of acceleration of a block can be calculated using the formula a = (vf - vi)/t, where a is the acceleration, vf is the final velocity, vi is the initial velocity, and t is the time interval.
The magnitude of acceleration of a block is affected by the net force acting on the block and its mass. A larger net force or a smaller mass will result in a larger magnitude of acceleration.
According to Newton's Second Law, the magnitude of acceleration of a block is directly proportional to the net force acting on the block and inversely proportional to its mass. This can be expressed as a = F/m, where a is the acceleration, F is the net force, and m is the mass.
Yes, the magnitude of acceleration of a block can be negative if the block is slowing down or changing direction. However, the negative sign does not indicate a decrease in magnitude, but rather a change in direction.