New to C++; reversing a number upto 5 digits in length

[zarentina]

Hello all, I hadn't touched a bit of programing until the start of this semester and it feels as if I've been thrown to the wolves. I am required to write a program that takes UP TO 5 digits, reverses it, and calculate the square roots of both. The code that I have thus far is;

#include<iostream> //required for cin, cout
#include<cmath>
using namespace std;
int main()

{
int n1,n2,n3,n4,n5,num;



cout<< "Please enter an integer, up to 5 digits in length" <<endl<<endl;
cin>>num;
cout<< "The Square root is:"<<sqrt(num)<<endl<<endl;
n5=num/10000; //
n4=(num%10000)/1000; //
n3=((num%10000)%1000)/100; //
n2=(((num%10000)%1000)%100)/10; //
n1=((((num%10000)%1000)%100)%10)/1; //

int num2=((n1*10000)+(n2*1000)+(n3*100)+(n4*10)+(n5*1)); // to declare second intiger

cout<< "The number in reverse is:" <<num2<<endl;
cout<< "The square root is:" <<sqrt(num2)<<endl;

system("pause");
return 0;
}

My only problem is with numbers that are less than 5 digits in length, when I have a number such as 234 when it reverses it the output sees it as 43200. How do I eliminate the trailing zeros so it won't throw off the square root of the reversed number.

Thanks,
Z

 

[I like Serena]

Welcome to PF, zarentina!

Perhaps you could put your number in a string buffer, reverse the string buffer, and convert it to an integer?
C++ supports various ways to do this...

 

[zarentina]

Thanks for the reply,

Could you further explain what that means or how I would go about doing it? I guess I didn't iterate that I am completely terrible and 100% lost when it comes to writing code. I'm not fishing for an answer as I have no qualms with doing the work on my own just a simple nudge in the right direction?

 

[I like Serena]

Well, the nudge is to take a look at the Standard C++ Library.
What kind of materials do you have to look stuff up on C++?
And do you know what the word "string" means in the context of programming?

The questions are:
1. How do you convert a number to a string?
2. How do you reverse the order of the characters in a string?
3. How do you convert a string to a number?

You could even google these questions!

 

[AlephZero]

Or, use a loop rather than separate variables for the 5 digits.

if n is the number and r is the reversed number, you could write a loop to do something like this:

Suppose you start with n = 1234 and r = 0
The first time through the loop, find the last digit of n (which is 4) and then make n = 123 and r = 4
The second time through, the last digit will be 3, and then make n = 12 and r = 43
Then n = 1 and r = 432
Then n = 0 and r = 4321
And exit the loop when n = 0

Work out the details for yourself. You will probably want to use another variable as a temporary place to remember the each "last digit" of n. But you only need one variable not five, because once you have updated r you don't need to remember the "last digit" and longer.

 

[zarentina]

I just wanted to thank you for the replies to this thread, I figured it out using a loop in place of separate variables. This was my final product, feel free to critique if necessary!


#include<iostream> //required for cin, cout
#include<cmath>
using namespace std;
int main()

{
int num;

cout<< "Please enter an integer, up to 5 digits in length" <<endl<<endl;
cin>>num;
cout<< "The Square root is:"<<sqrt(num)<<endl<<endl;

int r = num;
int rev = 0;

while (r>0)
{
rev = (rev * 10) + (r % 10);
r /= 10;
}

cout<< "The number in reverse is:" <<rev<<endl;
cout<< "The square root is:" <<sqrt(rev)<<endl;

system("pause");
return 0;
}


Thanks again,
Z

 

[I like Serena]

Looks good!