- #1
ranger1716
- 18
- 0
I have a question regarding a 4th order differential equation from an exam i just took.
we were asked to solve y^(4)-1=5 given y'(0)=y''(0)=y^(3)(0)=0
I started by factoring down to (r-1)(r+1)(r^2+1)=5.
I then found my general solution to be y=C_1e^6x+C_2e^4x+C_3e^2x+C_4e^-2x
Obviously I would then be left with four equations with four unknowns to solve for my constants. Would I need to use a solver and/or hand solve the equations in order to find the constants? I didn't have time to do that so I just put the equations into a matrix and said that the constants were all equal to zero.
Just thought I would ask what the right approach would be (a little to anxious to wait another week)
we were asked to solve y^(4)-1=5 given y'(0)=y''(0)=y^(3)(0)=0
I started by factoring down to (r-1)(r+1)(r^2+1)=5.
I then found my general solution to be y=C_1e^6x+C_2e^4x+C_3e^2x+C_4e^-2x
Obviously I would then be left with four equations with four unknowns to solve for my constants. Would I need to use a solver and/or hand solve the equations in order to find the constants? I didn't have time to do that so I just put the equations into a matrix and said that the constants were all equal to zero.
Just thought I would ask what the right approach would be (a little to anxious to wait another week)