Three same-mass freight cars, why force on each is not same ?

In summary, the question is asking for the forces that car C exerts on B and B exerts on A, in terms of the force F that the locomotive exerts on C. The solution to this problem is $$\vec{F}_{A}=\frac{\vec{F}}{3}$$, $$\vec{F}_{B}=\frac{2\vec{F}}{3}$$, and $$\vec{F}_{C}=\vec{F}$$. The confusion may arise from the lack of clarification in the question.
  • #1
ato
30
0
QUESTION
three cars of mass m are pulled with force F by a locomotive. Find forces on each cars ?

assuming the force F is exerted on car C and nearest to C is car B and remaining one is A.
[tex]\vec{F}_{A}[/tex] is total sum of all (interbody-) forces on car A . similarly [tex]\vec{F}_{B}[/tex] and [tex]\vec{F}_{C}[/tex] are defined.

assuming the forces that the question asks is [tex]\vec{F}_{A}[/tex],[tex]\vec{F}_{B}[/tex] and [tex]\vec{F}_{C}[/tex] and the given information is
$$\vec{F}_{CO}=\vec{F}$$

according to Newton's 2nd law
$$\vec{F}_{A}=\frac{d^{2}}{dt^{2}}m\vec{r}_{A}$$,
$$\vec{F}_{B}=\frac{d^{2}}{dt^{2}}m\vec{r}_{B}$$ and
$$\vec{F}_{C}=\frac{d^{2}}{dt^{2}}m\vec{r}_{C}$$

but since
$$\frac{d^{2}}{dt^{2}}\vec{r}_{A}=\frac{d^{2}}{dt^{2}}\vec{r}_{B}=\frac{d^{2}}{dt^{2}}\vec{r}_{C}$$, $$\frac{d}{dt}m =0$$

so above five equations would give
$$\vec{F}_{A}=\vec{F}_{B}=\vec{F}_{C}$$

according to superposition principle,
$$\vec{F}_{A}=\vec{F}_{AB}$$
because there is only one force i.e tension force due to string, exerted on A.
$$\vec{F}_{B}=\vec{F}_{BA}+\vec{F}_{BC}$$
because two tension forces (from both A and C) is acting on B.
$$\vec{F}_{C}=\vec{F}_{CO}+\vec{F}_{CB}$$
because one external force of magnitude F and one tension force from B.

according to 3rd law we also have,
$$\vec{F}_{AB}=-\vec{F}_{BA}$$ and
$$\vec{F}_{BC}=-\vec{F}_{CB}$$.

so from above five equations,
$$\vec{F}_{A}+\vec{F}_{B}+\vec{F}_{C}=\vec{F}_{CO}$$
hence
$$\vec{F}_{A}=\vec{F}_{B}=\vec{F}_{C}=\frac{\vec{F}}{3}$$
but i don't undertand why its wrong because the solution says
$$\vec{F}_{A}=\frac{\vec{F}}{3}$$,
$$\vec{F}_{B}=\frac{2\vec{F}}{3}$$ and
$$\vec{F}_{C}=\vec{F}$$

the only problem think i can think of is may be the question is asking for different forces , because there are forces that have same value for example ,
$$\vec{F}_{A}=\frac{\vec{F}}{3}$$,
$$\vec{F}_{BC}=\frac{\vec{2F}}{3}$$,
$$\vec{F}_{C0}=\vec{F}$$


thank you
 
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  • #2
The question is not asking for the net force on each car, which of course must be equal. It is asking for the force that C exerts on B and B exerts on A in terms of the force F that the locomotive exerts on C.
 
  • #3
so the question was indeed asking for $$\vec{F}_{CO}$$,$$\vec{F}_{BC}$$ and $$\vec{F}_A$$ .

i don't understand why not say so in the question, instead of being so short and confusing. i though the book was teaching physics not reading mind.

thanks for the help Doc Al
 

1. Why is the force on each freight car not the same?

The force on each freight car is not the same because of Newton's third law of motion, which states that for every action, there is an equal and opposite reaction. In this case, the force exerted on each freight car is the reaction force to the force exerted on the other cars in the system. This results in varying forces on each car.

2. How does the mass of the freight cars affect the force?

The mass of the freight cars does not directly affect the force on each car. The force is determined by the acceleration of the cars, which is influenced by the net external force acting on the system. However, the mass of the cars can indirectly affect the force as it contributes to the overall inertia of the system.

3. Is the force on the first car greater than the force on the last car?

No, the force on the first car is not necessarily greater than the force on the last car. The force on each car depends on the direction and magnitude of the external forces acting on the system, which can vary depending on the specific situation.

4. How does the distance between the cars affect the force?

The distance between the cars does not directly affect the force on each car. However, it can indirectly impact the force as it affects the overall dynamics and motion of the system. For example, a shorter distance between cars may result in a stronger force between them due to a stronger gravitational pull.

5. Can the force on each car ever be equal?

Yes, the force on each car can be equal if the system is in a state of equilibrium, where the net external force acting on the system is zero. This means that there is no acceleration or change in motion, resulting in equal forces on each car.

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