Industrial current to pneumatic convertor

In summary, for the given data of a current to pneumatic convertor, the suitable values for x and y are x = 50mm and y = 50mm. The equation for calculating Pout is Pout = (Kc * Y/A*X)Iin + Fs*Z/A*X, and for the given values of Pout = 1 bar and Iin = 20mA, the values of x and y can be calculated to be x = 50mm and y = 50mm.
  • #1
zulfiqar
1
0

Homework Statement


A Current to pneumatic convertor which is shown here in the attachment has the given data which is
Kc=2500N/A (constant of proportionality
X+Y = 100mm
Z=75mm
A=5cm^2

1-to check the response of I/P as per graph waht is the suitable value of x and y
2- what is the value of Fs


Homework Equations



Pout = (Kc*Y/A*X)Iin+Fs*Z/A*X

The Attempt at a Solution


Given data is
Kc =2500NA-1 or 2500,000mNA-1

X+Y = 100mm

Z=75mm

A= 5cm^2 or 500mm^2




Solution
The balance equation of the system is

Pout = (Kc * Y/A*X)Iin + Fs*Z/A*X

Y=MX+C




Now by looking the graph the intercept c of the line run through zero so
The Fs*z/A*X part of the equation iS neglected so new equation is lik
Pout = (Kc*Y/A*X) Iin

Or Y = MX





As per the graph the value of
Pout =1 bar or 100,000pascals
Iin = 20mA
now by putting these values in the above equation
100,000 = ( Kc*y/A*X) 20

Kc*Y/A*X = 5000

Now by putting the value of Kc and A

2500,000*Y/500*X = 5000

SO
Y/X = 1
Now as per the given data the

X+Y = 100
And Y = 100-X

Now by putting this value of X in the above equation


100-X/X = 1
100-X =1X
100 =1X+X
100 =2X
X =50mm

Now by putting this value of X in the given x+y =100 we will get the value

X+y = 100

50+Y = 100

Y = 100-50

Y = 50mm

so the value of x = 50mm and Y= 50mm
I am not sure this the correct solution and the unit selection is correct or not
If any friend has some idea about this please guide me
 

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  • #2
Your values for x and y look okay to me.
 

1. What is an industrial current to pneumatic convertor?

An industrial current to pneumatic convertor is a device that converts electrical signals from industrial equipment into compressed air signals. This allows for control and operation of pneumatic devices using electrically powered equipment.

2. How does an industrial current to pneumatic convertor work?

The convertor works by receiving input from current sensors attached to the electrical equipment. It then converts the signal into a proportional compressed air signal using a transducer, which can be adjusted to control the output pressure. This compressed air signal is then sent to the pneumatic devices for operation.

3. What are the advantages of using an industrial current to pneumatic convertor?

One advantage is that it allows for the use of electrically powered equipment to control and operate pneumatic devices, which can be more efficient and cost-effective. It also eliminates the need for complex and expensive electrical control systems.

4. What types of industrial equipment can be used with a current to pneumatic convertor?

Various types of industrial equipment can be used, such as pumps, motors, valves, and sensors. As long as the equipment has an electrical signal output, it can be connected to the convertor for operation.

5. Are there any maintenance or safety considerations when using an industrial current to pneumatic convertor?

Regular maintenance, such as checking for leaks and ensuring proper calibration, is important to ensure the convertor is functioning correctly. Safety precautions should also be taken, such as following proper electrical and pneumatic safety guidelines, to prevent accidents or damage to equipment.

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