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CONBOSS
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Easy N2L question... grade 11 physics
Problem: A 500g dynamics cart is attached to a 50g mass, which is suspended over a pulley. When released from rest, it took 1.5 s for the cart to move a distance of 1m.
Find: a) acceleration of cart,
b) friction between cart and track
Attempt; a) Given: Δd=1m, Δt=1.5s
Δv= Δd/Δt
Δv=1/1.5
Δv=.666 m/s
a=Δv/Δt
a=.666/1.5
a=.444 m/s²
Thus, ave. acceleration of cart = .444 m/s²
b) Given: Fapp = 0.49 N, mcart=.500 kg, a=.444 m/s²
FNet= ma → (.5)(.444)
FNet= .222
FNet= Fapp + f + FN + Fg (FN & Fg are redundant)
.222= 0.49 + f → .222 - .49 = f
f= -.268 N
Therefore friction = .268 N
Problem: A 500g dynamics cart is attached to a 50g mass, which is suspended over a pulley. When released from rest, it took 1.5 s for the cart to move a distance of 1m.
Find: a) acceleration of cart,
b) friction between cart and track
Attempt; a) Given: Δd=1m, Δt=1.5s
Δv= Δd/Δt
Δv=1/1.5
Δv=.666 m/s
a=Δv/Δt
a=.666/1.5
a=.444 m/s²
Thus, ave. acceleration of cart = .444 m/s²
b) Given: Fapp = 0.49 N, mcart=.500 kg, a=.444 m/s²
FNet= ma → (.5)(.444)
FNet= .222
FNet= Fapp + f + FN + Fg (FN & Fg are redundant)
.222= 0.49 + f → .222 - .49 = f
f= -.268 N
Therefore friction = .268 N