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Statics  Method of Sections 
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#1
Nov1012, 02:09 AM

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IHi guys with part b of this question im having trouble. I have cut it it at the specified members and used the top half. Now i take the moment at A to get the force in BC. (CW+)M@A=(6*3)+(6cos(30)*3)=0, But when you solve this it dosnt give you the answer its supposed to be, Im probably blind & missing something. Please check out the attachments i provided some more info on it.
Thankyou in Advance. 


#2
Nov1012, 04:40 AM

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#3
Nov1012, 04:53 AM

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Sorry man, its up now



#4
Nov1012, 11:45 AM

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Statics  Method of Sections
Where do you get 30 degrees from? Check your triangles.



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