Limit word problem- helicopter jump

Let's break down the problem into three parts:In summary, Ayida, a stuntperson, will use a jetpack to jump out of a helicopter at a height of either 100m or 200m. She wants to time the use of the jetpack so that she lands with zero velocity. To solve this, we can use the equation y = y_{0} +v_{y0}t + \frac{1}{2}a_{y}t^{2} and differentiate it to get v_{y} = v_{y0}+a_{y}t. This is a standard equation for displacement with constant acceleration. The three parts of the problem are determining when Ayida should turn on her
  • #1
Aoiro
8
0
Hi, I need help with this question

At a publicity event, Ayida, a stuntperson, will jump out of a helicopter with a jetpack on her back. The jetpack allows her to achieve a net upward acceleration of 4.4m/s^2 for a single interval of maximun length 10s. Ayida wants to time the use of the jetpack so that she lands with a zero velocity.
a) If the helicpter is 100m hight, when should Ayida turn on her jetpack? When will she land?
b) If the helicopter is 200m hight, when should Ayadia turn on her jetpack? when will she land?
c) What is the maximum height from which Ayida can jump to land with zero velocity?

I don't know where to start can someone explain this problem thanks.
 
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  • #2
Use the equation [tex] y = y_{0} +v_{y0}t + \frac{1}{2}a_{y}t^{2} [/tex]. You can differentiate this to get [tex] v_{y} = v_{y0}+a_{y}t [/tex]
 
Last edited:
  • #3
How did you get that equation?
 
  • #4
Aoiro said:
How did you get that equation?

It's a 'standard' equation of displacement for motion with constant acceleration.
 

1. How do you solve a limit word problem involving a helicopter jump?

The first step is to identify the given information such as the height of the helicopter, the initial velocity of the jumper, and the acceleration due to gravity. Then, use the equations of motion to set up an equation for the height of the jumper as a function of time. Finally, take the limit as time approaches the maximum height to find the final height of the jumper.

2. What is the significance of using a limit in a helicopter jump word problem?

A limit allows us to find the exact value of a quantity that is constantly changing, such as the height of the jumper in a helicopter jump. By taking the limit as time approaches a specific value, we can find the exact height of the jumper at that time without having to rely on approximations.

3. Can a limit word problem involving a helicopter jump have more than one solution?

Yes, a limit word problem can have more than one solution. This often occurs when there are multiple maximum or minimum points involved in the problem. It is important to carefully analyze the given information and equations to determine all possible solutions.

4. How can real-life factors, such as air resistance, affect a limit word problem involving a helicopter jump?

Real-life factors, such as air resistance, can affect the accuracy of the solution to a limit word problem involving a helicopter jump. In most cases, these factors are negligible, but in more complex problems, they may need to be taken into consideration to obtain a more accurate solution.

5. Are there any common mistakes to avoid when solving a limit word problem involving a helicopter jump?

One common mistake is to use the wrong equation for the given problem. It is important to carefully read and understand the given information to determine which equations should be used. Another mistake is to not simplify the equation before taking the limit, which can lead to incorrect solutions.

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