Lienard-Wiechert potential for 2 discrete Qs

B)(1/r2 + 1/(r2 + dr) - dr/r2^2)= q(1 + B)(2/r2 + dr/r2^2 - dr/r2^2)= 2q(1 + B)/r2In summary, the potential at the observation point for two discrete charges q1 @r1 and q2 @r2 with r1 > r2 and both traveling at velocity v away from and along r1, r2 can be calculated using the Lienard-Wiechert potential. However, there were some errors in the derivation, and the correct expression for the potential is 2q(1 + B)/r2
  • #1
jmc8197
9
0
I've tried a simple derivation of the Lienard-Wiecher potential for 2 discrete charges separated by dr, but end up with a result which isn't the same as the theoretically correct version:

Take two charges q1 @r1, q2 @r2 with r1 > r2, dr = r1 - r2, parallel
and both traveling at velocity v away from and along r1, r2. The
observation point is at r = 0. The potential of q1 that arrives at q2
is from a retarded time t' = dr/(v + c). This is when q1 was at r2 +
dr - vt' = r2 + dr - v dr/(v + c) = r2 + dr/(1 + B) where B = v/c. So
the potential at the observation point can be replaced by an
equivalent static q1 and q2 separated by dr/(1 + B), equivalent to
increasing the charge density by (1 + B) at r.

The total potential is then q2/r2 + q1/(r2 + dr/(1 + B)) which for
small dr and q1 = q2 = q can be written using the first two terms of a taylor expansion:


q/r2 + q/r2 (1 - dr/(1 + B)r2)


= 2q/r2 - q dr/(1 + B)r2^2 )


I'm not sure how to proceed further, since I was hoping to end up with
an expression 2q/(1 + B) r2. Can anyone see where I've gone wrong?
 
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  • #2


Thank you for sharing your derivation of the Lienard-Wiechert potential. It seems like you are on the right track, but there are a few errors in your calculations.

Firstly, in your expression for the potential at the observation point, you have used the charge density of q1 to be (1 + B) at r, which is incorrect. The correct charge density at r would be q1, as q1 is the only charge present at r.

Secondly, in your expression for the equivalent static charge, you have used the distance between q1 and q2 to be dr/(1 + B). This is incorrect as the distance between q1 and q2 would be dr, as they are separated by dr in the direction of their velocities.

Finally, in your final expression, you have used the charge density of q1 to be q, which is incorrect. The charge density of q1 would be q at r2, but at r2 + dr, the charge density would be q(1 - dr/(1 + B)r2).

Correcting these errors, the final expression for the potential at the observation point would be:

q/r2 + q(1 - dr/(1 + B)r2)/(r2 + dr)

= q/r2 + q(1 - dr/(1 + B)r2)/(r2(1 + dr/r2))

= q/r2 + q(1 - dr/(1 + B)r2)/(r2 + dr)

= q/r2 + q/(r2 + dr) - q dr/(1 + B)r2(r2 + dr)

= q/r2 + q/(r2 + dr) - q dr/(1 + B)r2^2 - q dr/(1 + B)r2dr

= q/r2 + q/(r2 + dr) - q dr/(1 + B)r2^2 - q(1 - B)dr/r2

= q(1 + B)/r2 + q/(r2 + dr) - q dr/r2^2 - q(1 - B)dr/r2

= q(1 + B)/r2 + q/(r2 + dr) - q(1 + B)dr/r2^2

= q(1 + B)/r2 + q(1 + B)/(r2 + dr) - q(1 + B)dr/r2^
 

What is the Lienard-Wiechert potential for 2 discrete Qs?

The Lienard-Wiechert potential for 2 discrete Qs is a mathematical formula that describes the electromagnetic potential at a point in space due to two discrete charged particles moving at constant velocities. It takes into account both the current position and the past history of the particles, and is a key component in understanding the behavior of electromagnetic fields.

How is the Lienard-Wiechert potential calculated?

The Lienard-Wiechert potential is calculated using the velocity and position of the two charged particles, as well as the distance between the particles and the point in space where the potential is being calculated. It involves complex mathematical equations and is often solved using computer simulations or specialized software.

What are the applications of the Lienard-Wiechert potential for 2 discrete Qs?

The Lienard-Wiechert potential has important applications in various fields such as electromagnetism, astrophysics, and particle physics. It is used to study the behavior of electromagnetic fields and helps in understanding the interactions between charged particles in different systems.

What are some limitations of the Lienard-Wiechert potential for 2 discrete Qs?

While the Lienard-Wiechert potential is a useful tool in understanding electromagnetic fields, it has some limitations. It assumes that the particles are point charges and does not take into account the effects of quantum mechanics. It also becomes more complicated in systems with more than two particles.

Are there alternative models to the Lienard-Wiechert potential for 2 discrete Qs?

Yes, there are alternative models that describe the behavior of electromagnetic fields in systems with multiple charged particles. These models may take into account effects such as quantum mechanics and can provide a more accurate description of the system. However, the Lienard-Wiechert potential remains a widely used and accepted model in many applications.

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