How do i solve this question? please maths exam tm?

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In summary, the question asks for the area of a rectangle with a given perimeter of 140cm and a length to width ratio of 4:3. To solve, you can set up an expression for the perimeter and use the given ratio to find the length and width. The area can then be calculated using the length and width values.
  • #1
beccalicious87
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How do i solve this question?? urgent please maths exam tm?

The question is:
The perimeter of a rectangel is 140cm. The length with width ratio is 4:3. Find the area??

Could someone please help me with this question??
 
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  • #2
Well, you're given the value of the perimeter, and you should know that the perimeter is just the sum of the sides of the rectangle, which is twice the sum of the length plus width: perimeter = 2*(length + width).

You know that length/width = 4/3, so you can express length in terms of width, plug into your perimeter expression above, and solve for the width. Then you can calculate the length from the width.

Finally, area is just length*width.
 
  • #3
Urgent as my maths exam is tomorrow.

To solve this question, you first need to find the length and width of the rectangle. Since the length to width ratio is 4:3, we can set up the following equation:

4x + 3x = 140cm

Solve for x by combining like terms and dividing both sides by 7:

7x = 140cm
x = 20cm

Now, we can find the length and width by multiplying x by the corresponding ratio numbers:

Length = 4x = 4(20cm) = 80cm
Width = 3x = 3(20cm) = 60cm

To find the area, we use the formula A = length x width. In this case, it would be:

A = 80cm x 60cm = 4800cm²

Therefore, the area of the rectangle is 4800cm². Make sure to double check your calculations and units before submitting your answer. Best of luck on your exam tomorrow!
 

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