Calculate Force Magnitude & Attractiveness of Electron Transfer

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In summary, the formula for calculating the force magnitude of an electron transfer is given by Coulomb's Law, which states that the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. The distance between two charged particles is typically measured in meters and is used in the denominator of Coulomb's Law. The force magnitude of an electron transfer cannot be negative as it only determines the magnitude, not the direction. The attractiveness of an electron transfer, or the difference in charge between the particles, directly affects the force magnitude. Other factors that can affect the force magnitude include the presence of other charged particles or objects nearby, which can create an electric field.
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dgresch
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Two neutral metal spheres are separated by 0.5m when 3.0x1013 electrons are transferred from one to the other. Calculate the resultant force magnitude and whether it is attractive or repulsive.


q=Ne
F=kq1q2/r2
I think?


q=(3.0x1013)(-1.602x10-19C)
q=-4.8uC

F=(9x109)(-4.8uC)(4.8uC)/(0.5m)2
F=-0.83N [attractive]

Does this seem correct?
 
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  • #2
Looks okay!
 
  • #3
thanks for the confirmation
 

1. What is the formula for calculating the force magnitude of an electron transfer?

The formula for calculating the force magnitude of an electron transfer is given by Coulomb's Law, which states that the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

2. How is the distance between two charged particles determined in the calculation of force magnitude?

The distance between two charged particles is typically measured in meters and is the distance between their centers of charge. This distance is used in the denominator of Coulomb's Law to account for the decrease in force as the distance between particles increases.

3. Can the force magnitude of an electron transfer be negative?

No, the force magnitude of an electron transfer cannot be negative. Coulomb's Law only determines the magnitude of the force, not the direction, which is determined by the charges of the particles involved. A negative sign may be used to represent the attractive force between opposite charges, but the magnitude itself is always positive.

4. How does the attractiveness of an electron transfer affect the force magnitude?

The attractiveness of an electron transfer, or the difference in charge between the two particles involved, directly affects the force magnitude. The greater the difference in charge, the stronger the force will be. This is because the force is directly proportional to the product of the charges involved.

5. Are there any other factors that can affect the force magnitude of an electron transfer?

Yes, there are other factors that can affect the force magnitude of an electron transfer, such as the presence of other charged particles or objects nearby. These external factors can create an electric field that can influence the force between the charged particles, altering the calculated force magnitude.

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