- #1
mr_miyagi
- 4
- 0
This is the problem:
A 15.0 kg box is slid down a 6.00 meter high ramp to pick up speed to do a vertical loop-the-loop whose radius is 2.00 meters. All surfaces are conveniently frictionless.
Part A) asks to find the Speed at the top of the loop-the-loop.
Part B) asks to find the Normal force on the box at the top of it's motion.
I'm just not sure I've solved it correctly.
Here's what I did it:
A)
PEi + KEi = PEf + KEf
(1/2)*m*vi2 + m*hi*g = (1/2)*m*vf2 + m*hf*g
0 + 6mg = (1/2)*m*vf2 + 4*m*g
6g = vf2/2 + 4g
vf = sqrt(4g) = 6.26m/s
B) Normal = Centripedal Force - mg = m*v2/r - mg = 15*(6.262/2) - 15*9.8 = 117.6 N
A 15.0 kg box is slid down a 6.00 meter high ramp to pick up speed to do a vertical loop-the-loop whose radius is 2.00 meters. All surfaces are conveniently frictionless.
Part A) asks to find the Speed at the top of the loop-the-loop.
Part B) asks to find the Normal force on the box at the top of it's motion.
I'm just not sure I've solved it correctly.
Here's what I did it:
A)
PEi + KEi = PEf + KEf
(1/2)*m*vi2 + m*hi*g = (1/2)*m*vf2 + m*hf*g
0 + 6mg = (1/2)*m*vf2 + 4*m*g
6g = vf2/2 + 4g
vf = sqrt(4g) = 6.26m/s
B) Normal = Centripedal Force - mg = m*v2/r - mg = 15*(6.262/2) - 15*9.8 = 117.6 N