- #1
- 4,807
- 32
Now I have to evaluate
[tex]\int_{-\infty}^{\infty} e^{-Bx^2} e^{-iAx} dx[/tex]
Splitting it in two using Euler's identity show that the imaginary part is 0 (cuz integrand is odd). Remains the real part
[tex]2 \int_0^{\infty} cos(-Ax) e^{-Bx^2} dx[/tex]
for which integration by parts leads nowhere.
[tex]\int_{-\infty}^{\infty} e^{-Bx^2} e^{-iAx} dx[/tex]
Splitting it in two using Euler's identity show that the imaginary part is 0 (cuz integrand is odd). Remains the real part
[tex]2 \int_0^{\infty} cos(-Ax) e^{-Bx^2} dx[/tex]
for which integration by parts leads nowhere.