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Finding Slope of a Tangent Line to a Parabola |
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| Jan14-13, 05:01 PM | #1 |
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Finding Slope of a Tangent Line to a Parabola
1. The problem statement, all variables and given/known data
I've got the equation of a parabola [itex]y=2x^2-4x+1[/itex] with point (-1,7) and a tangent line running through it the point. I'm supposed to find the equation of the line. Simultaneously solve this equation with that of the parabola, place the results in form [itex]ax^2+bx+c[/itex], and find the slope of the tangent line. 2. Relevant equations [itex]y=2x^2-4x+1[/itex] [itex]y=m(x--1)+7[/itex] [itex]ax^2+bx+c[/itex] 3. The attempt at a solution I was supposed to find the equation of the line using the point slope equation and I did, I placed it above. The problem lies when I try to set the equations equal to each other [itex]m(x+1)+7=2x^2-4x+1[/itex]and place the results in [itex]ax^2+bx+c[/itex] form. I guessed that [itex]a=2[/itex] and it was correct. However b is not [itex]-4x-mx[/itex] and c is not [itex]m-6[/itex] |
| Jan14-13, 05:35 PM | #2 |
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It looks like you are on the right track, but have some trouble with your bookkeeping.
If you have m(x + 1) = mx + m = 2x² - 4x + 1, start by bringing everything to one side of the equals sign: 2x² - 4x - mx + 1 - m = 0. Now carefully compare this to the given form, ax² + bx + c. Try rewriting the equation to get this: 2x² + (....)x + (...) = 0. You will be able to read off b and c, but this time with the correct signs :) (Also, don't forget, as I initially did, that it stays an equation -- after the rewrite there will be "= 0" on the right hand side). |
| Jan14-13, 09:44 PM | #3 |
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Recognitions:
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I wish using a little differentiation were justified here. for the y=parabola,
d/dx of 2x^2-4x+1 is 4x-4. Value of derivative when x=-1 becomes -8, so slope is -8 for the line. Now we have both the (given) point, and the slope of the line. I just do not see the less advanced algebra trick to solve the question. |
| Jan14-13, 11:52 PM | #4 |
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Recognitions:
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Finding Slope of a Tangent Line to a Parabola |
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