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Lorentz transformation of delta function 
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#1
Feb814, 03:11 AM

P: 27

For two body decay, in CM frame, we know that the magnitude of the final particle momentum is a constant, which can be described by a delta function, ##\delta(\vec{p^*}\vec{p_0^*})##, ##\vec{p_0^*}## is a constant.
When we go to lab frame (boost in z direction), what's the Lorentz transformation of the delta function? regards! 


#2
Feb814, 03:10 PM

PF Gold
P: 354

What do you mean by "which can be described by a delta function" ?



#3
Feb814, 07:37 PM

P: 27

Maybe my example of two body decay is not so suitable, but my question is just for mathematics, that is the Lorentz transformation of ##\delta(\vec{p}\vec{p_0^*})## 


#4
Feb914, 07:53 AM

Sci Advisor
Thanks
P: 4,160

Lorentz transformation of delta function



#5
Feb1014, 03:35 AM

PF Gold
P: 354

Chenkb,
Are talking about a distribution function in the momentum space, and about how this function might evolve with an interaction? Are you considering 3momentum or 4momentum? 


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