- #1
Grekory
- 2
- 0
When I'm given do, ho, and hi. How would i solve for di
Normally i would do -di/do = hi/ho and cross-multiply but I'm not sure how the negative comes into effect.
do = object distance
di = image distance
ho = object height
hi = image height
If...
ho = 3cm
hi = 4cm
do = 5cm
What would be di?
Thanks
Normally i would do -di/do = hi/ho and cross-multiply but I'm not sure how the negative comes into effect.
do = object distance
di = image distance
ho = object height
hi = image height
If...
ho = 3cm
hi = 4cm
do = 5cm
What would be di?
Thanks