Convert triangle vertices to double integral polar coordiantes

In summary, the task is to integrate the function f(x,y) = sqrt(x^2+y^2) over a triangle with vertices (0,0), (0,sqrt2), and (sqrt2, sqrt2). To solve this, the double integral is converted to polar coordinates using the equations x=rcosO and y=rsinO. The correct bounds for the integral are 0 to pi/4 for theta and 0 to sqrt2 sec(r^2) for the radius. The bounds for theta are determined by the line y=x, which cuts the triangle at a 45 degree angle.
  • #1
ramses07
11
0

Homework Statement



integrate

f(x,y) = sqrt(x^2+y^2)

over triangle with vertices (0,0) (0,sqrt2) (sqrt 2, sqrt 2)

Homework Equations



x= rcosO, y = rsinO

x^2+y^2=r^2

The Attempt at a Solution



im supposed to use a double integral converted to polar coordinates,
so i used the bounds int. 0 to pi/4 int. 0 to sqrt 2 sec (r^2) drdO

are these the correct bounds? because i can't seem to find the answer.
 
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  • #2
I think your bounds for theta should be pi/4 to pi/2
 
  • #3
how do you know what the bounds are?
 
  • #4
because the line y=x cuts it at a 45 degree angle and x=0 goes up to 90 so it goes from 45 to 90
like cutting a wedge out of a circle , but the radius is different , i think your bounds for the radius are correct.
 

1. What is the purpose of converting triangle vertices to double integral polar coordinates?

The purpose of converting triangle vertices to double integral polar coordinates is to simplify the process of evaluating integrals over a triangle. Polar coordinates make it easier to integrate functions with circular or symmetric patterns, which are commonly found in triangles.

2. How do you convert triangle vertices to double integral polar coordinates?

To convert triangle vertices to double integral polar coordinates, you first need to determine the center of the triangle and the length of each side. Then, you can use the formula r = sqrt(x^2 + y^2) to convert the x and y coordinates of each vertex into polar coordinates (r, θ). Finally, you can use the polar coordinates to set up the double integral and integrate over the triangle.

3. What are the benefits of using double integral polar coordinates?

Using double integral polar coordinates can make it easier to evaluate integrals over regions with circular or symmetric patterns. It can also help to simplify the integration process and reduce the number of variables in the integrand.

4. In what situations would you use double integral polar coordinates?

You would use double integral polar coordinates when evaluating integrals over regions with circular or symmetric patterns, such as triangles, disks, or rings. It can also be useful when dealing with functions that have polar coordinates as their natural domain.

5. Are there any limitations to using double integral polar coordinates?

One limitation of using double integral polar coordinates is that it can only be used for integrals over regions with circular or symmetric patterns. It may also be more difficult to visualize and set up the integral in polar coordinates compared to Cartesian coordinates.

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