Object visibility and size-to-distance ratios

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In summary, the relationship between the size of an object and the distance at which it becomes non-visible is affected by both the resolution of the human eye and the luminosity of the object. The inverse-square law can be used to calculate the distance at which an object becomes imperceptible, but this does not take into account the effects of imperfectly-transparent air. Therefore, a smaller object at a closer distance may appear to be the same size as a larger object at a further distance due to contrast differences.
  • #1
jimgavagan
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Kind of just a random question I thought of that I thought was a physics question - I apologize in advance if it is not a physics question.

Here goes:

What is the relationship between the size of an object and the distance from your eye at which the object becomes non-visible? Obviously the larger an object, the longer the distance at which the object remains perceptible, but I'm sure the size-to-distance ratios for all objects are the same, no?
 
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  • #2
Depends how bright the object is. You may see something really small (e.g. laser pointer aimed at you) from several miles.
 
  • #3
Well, there are 2 different things here. The first is the resolution of your eye and the apparent size of what you can see. The other is the luminosity of the object. For example, your eye is not able to see the "size" of a star in the sky. But the amount of light it emits causes it to be visible even as a "point object".
 
  • #4
jimgavagan said:
Obviously the larger an object, the longer the distance at which the object remains perceptible, but I'm sure the size-to-distance ratios for all objects are the same, no?

Yes, you can use similar triangles to show that an object that is twice as far but twice as large will appear the same shape in the human brain. Other posters made the important point that if the object is radiating isotropically, the intensity of light falls like 1/r^2. So this object, when expanded and moved twice as far away, will have the same shape but not the same brightness.
 
  • #5
I understand the brightness thing, but let's just assume there's not a lot of light anywhere in this scenario. I'm just wondering if the ratio of the distance-to-size of an object is the same for all objects regardless of initial size at 0 distance and, if it is the same for all objects, what that ratio approximately is.

Assume that all objects do not radiate light and do not reflect light.

I'd also note though that clearly a silver balloon let go into the sky reflects light and yet there's a certain distance at which it's no longer perceptible.
 
  • #6
jimgavagan said:
let's just assume there's not a lot of light anywhere in this scenario. [...] Assume that all objects do not radiate light and do not reflect light.
Absolute darkness. Under such scenario you would see nothing, I am afraid.
 
  • #7
Note I did not say absolute darkness, but dimness.
 
  • #8
jimgavagan said:
I understand the brightness thing, but let's just assume there's not a lot of light anywhere in this scenario. I'm just wondering if the ratio of the distance-to-size of an object is the same for all objects regardless of initial size at 0 distance and, if it is the same for all objects, what that ratio approximately is.

Assume that all objects do not radiate light and do not reflect light.

I'd also note though that clearly a silver balloon let go into the sky reflects light and yet there's a certain distance at which it's no longer perceptible.

I believe you want the inverse-square law or something similar. For example, if I double the distance from an object, both its X and Y length appear to decrease by half. The means that the apparent area of the object is now 1/4 what it was.

See here: http://en.wikipedia.org/wiki/Inverse-square_law
 
  • #9
Inverse square law looks right. So how do we solve the inverse square equation to figure out the distance at which an object becomes imperceptible given the size of the object?
 
  • #10
jimgavagan said:
Inverse square law looks right. So how do we solve the inverse square equation to figure out the distance at which an object becomes imperceptible given the size of the object?

Imperceptible meaning that you can't see the object's SIZE? Or imperceptible that we can't see it because it becomes so dim?
The star Deneb has a radius of 1 AU, meaning that its physical size is the same as the radius of Earths orbit around the sun, yet we cannot see its size. However Deneb has such luminosity that we can still see it from Earth. This is because the angular resolution of our eye is not enough to see the apparent size, but it can see the intensity of the light as a point source.
 
  • #11
MikeyW said:
Yes, you can use similar triangles to show that an object that is twice as far but twice as large will appear the same shape in the human brain. Other posters made the important point that if the object is radiating isotropically, the intensity of light falls like 1/r^2. So this object, when expanded and moved twice as far away, will have the same shape but not the same brightness.
No. This cancels out.

When you expand it, you are expanding it squared. Square A, whose surface is 10mx10m (100m^2) at 100m distance will have the same apparent brightness as Square B, whose surface is 20mx20m (400m^2) at 200m distance.

This is obvious if you note that, since square A will exactly and perfectly eclipse square B, their light cones are also identical.

This is also obvious if you close one eye. Without contextual clues, you will not be able to tell if you are looking at Square A, 100m away, or Square B, 200m away. (That's partly why we have two eyes.)
 
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  • #12
The one thing that will not scale is imperfectly-transparent air.

On earth, a 1m object at 100m will be noticeably higher in contrast than a 100m object at 10,000m.
 
  • #13
Drakkith: Yes, I mean imperceptible in size - nothing to do with brightness/dimness.

DaveC:

"On earth, a 1m object at 100m will be noticeably higher in contrast than a 100m object at 10,000m."

This is more along the lines of what I'm getting at. So, why wouldn't they be the exact same apparent size, then? What distance would the 100m object have to be to appear to be the same size as the 1m object at 100m?
 
  • #14
jimgavagan said:
"On earth, a 1m object at 100m will be noticeably higher in contrast than a 100m object at 10,000m."

This is more along the lines of what I'm getting at. So, why wouldn't they be the exact same apparent size, then?
They would be exactly the same apparent size. :grumpy:

jimgavagan said:
What distance would the 100m object have to be to appear to be the same size as the 1m object at 100m?
10,000m!You didn't read what I wrote. The contrast will be higher (more blacks and whites = more visible), but this is due to atmospheric effects.If you eliminated atmo effects (say, doing the experiment in space) (and also eliminating parallax clues), a 1m object at 100m would be totally indistinguishable from a 100m object at 10000m.
 
  • #15
daily said:
esolution of your eye and the apparent size of what you can see.
Regards
http://www.da-ily.com"

What?
 
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  • #16
when the distance of any object is less than 25cm,It become invisible (or) less quality.this is the nature of human eye.
In humans there exists two types of sights.those are
1.short sight
2.long sight

1:-short sight means the persons have some distinct area around himself.That area only be seen by him.
2:-long sight means the person have some distinct area around himself.That area could not be seen by him.He can see the surroundings out of this area.
 
  • #17
maruthisarat said:
when the distance of any object is less than 25cm,It become invisible (or) less quality.this is the nature of human eye.
No. It may be out of focus, but he will most certainly be able to see it.

maruthisarat said:
In humans there exists two types of sights.those are
1.short sight
2.long sight
There is a continuum, which includes both 1] and 2] as well as neither 1] nor 2].

maruthisarat said:
1:-short sight means the persons have some distinct area around himself.That area only be seen by him.
2:-long sight means the person have some distinct area around himself.That area could not be seen by him.He can see the surroundings out of this area.

Again, no. It may be out of focus, but he will most certainly be able to see it, whether he is near-sighted or far-sighted.
 
  • #18
No,when the distance is less than 25cm,he can see but it is not clear.
To prove put your palm 25 cm before eye and move it towards your eye.
Then eye is strained and image will be not clear.
 
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  • #19
maruthisarat said:
No,when the distance is less than 25cm,he can see but it is not clear.
Correct.

The first time you said this you were claiming it would be "invisible". Perhaps just a poor choice of word?
 
  • #20
maruthisarat said:
No,when the distance is less than 25cm,he can see but it is not clear.
To prove put your palm 25 cm before eye and move it towards your eye.
Then eye is strained and image will be not clear.

Exactly, the image will be out of FOCUS and will appear blurry. Invisible means that something is completely incapable of being seen in any way.
 

1. What is object visibility and why is it important in scientific research?

Object visibility is the ability to see and observe an object with the naked eye or with scientific instruments. It is important in scientific research because it allows us to study and understand the properties and behavior of objects, which can provide valuable insights and knowledge.

2. How is the size-to-distance ratio of an object determined?

The size-to-distance ratio of an object is determined by measuring its physical size and its distance from the observer. This can be done through various methods such as triangulation, parallax, or using specialized instruments like telescopes or microscopes.

3. What factors can affect the visibility and size-to-distance ratio of an object?

There are several factors that can affect the visibility and size-to-distance ratio of an object, including the brightness and contrast of the object, atmospheric conditions, and the quality of the observing instrument. The angle and direction of observation can also play a role.

4. How does the inverse square law relate to object visibility and size-to-distance ratio?

The inverse square law states that the intensity of light or radiation from a source decreases as the square of the distance from the source increases. This means that the farther an object is from an observer, the less visible it becomes and the smaller its apparent size appears.

5. Can object visibility and size-to-distance ratios be used to estimate the size and distance of objects in space?

Yes, object visibility and size-to-distance ratios are important tools in astrophysics for estimating the size and distance of objects in space. By measuring the apparent size and brightness of celestial objects, scientists can use these ratios to calculate their actual size and distance from Earth.

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