Triple integral w/ spherical subsitution

That is 2. So the answer is 2\pi\int_0^t f(p^2) p^2 dp.In summary, the problem involves finding the derivative of a function F(t) that is defined as the triple integral of a differentiable function f(x) over a spherical region. Using a substitution, the integral can be simplified to an easier form. The final solution involves evaluating a simple integral.
  • #1
dumbfoundead
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Homework Statement


f(x) is a differentiable function let
[itex]F(t)= \int\int\int_{x^2+y^2+z^2\leq t^2} f(x^2+y^2+z^2) dx dy dz [/itex]

compute F[itex]^{'}[/itex](t)

Homework Equations



x=p sin [itex]\phi[/itex] cos[itex]\theta[/itex]
y= p sin [itex]\phi[/itex] sin[itex]\theta[/itex]
z= p cos [itex]\phi[/itex]

spherical bounds 0<p<t 0<[itex]\phi[/itex]<[itex]\Pi[/itex] 0<[itex]\theta[/itex] < 2[itex]\Pi[/itex]

p^2 sin[itex]\phi[/itex] = jacobian determinant

3. The attempt at a solution

carried through the substitution [itex]\int\int\int f(p^2) p^2 sin \phi dp d\phi d\theta[/itex]

dont know how to evaluate [itex]\int[/itex]f(p^2) sin[itex]\phi[/itex] d[itex]\phi[/itex]?




 
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  • #2
Be careful about putting those repeated copies of the template in your questions.

The remaining integral is trivial. Your function is independent of [itex]\phi[/itex] so the [itex]\phi[/itex] integration is trivial; it's just the integral of [itex]sin(\phi)[/itex]
 

1. What is triple integral with spherical substitution?

Triple integral with spherical substitution is a mathematical technique used to calculate the volume under a three-dimensional surface, where the boundaries are defined in spherical coordinates.

2. When is triple integral with spherical substitution used?

Triple integral with spherical substitution is often used in physics and engineering applications, where spherical symmetry is present, such as in the calculation of electric fields or gravitational forces.

3. How is a triple integral with spherical substitution set up?

To set up a triple integral with spherical substitution, the given function and boundaries are first converted from Cartesian coordinates to spherical coordinates. The triple integral is then written as a product of three single integrals, one for each variable (radius, inclination, and azimuth angle).

4. What is the advantage of using spherical coordinates in a triple integral?

Spherical coordinates simplify the calculation of triple integrals by reducing the number of variables and making the integrand more manageable. This is especially useful when the boundaries of the volume have spherical symmetry.

5. Are there any limitations to using spherical coordinates in a triple integral?

Yes, spherical coordinates are not suitable for every type of volume. They are most effective when the boundaries of the volume have spherical symmetry. In some cases, it may be necessary to use other coordinate systems, such as cylindrical or Cartesian coordinates, to evaluate the triple integral.

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