# World's hardest easy problem

by namanjain
Tags: hardest, world
 P: 49 check out this question on the webpage http://thinkzone.wlonk.com/MathFun/Triangle.htm and please give me it's solution [THANKS FOR EVEN TRYING]
 P: 97 I haven't the solution, I get the equation x + y = 130, where x and y are angles. If $x, y \in Z^+$ This is a diophantine equation. We know: x, y > 0. y > x. And y is greater than 90 degrees. the most probable angles: $x=20^o\,\, ,y=110^o$ or $x=30^o\,\, ,y=100^o$
 PF Gold P: 520 nevermind
PF Gold
P: 520

## World's hardest easy problem

I tried a couple of things but didn't solve it yet , but there's probably a way to build your way up to the x angle using the tricks in my sketch (just don't have the patience to construct the triangles properly and doing it now):
Attached Thumbnails

 Mentor P: 7,292 Simple geometry is all that is required. Why can't you do this for yourself? Don't give up so easy.
P: 49
 Quote by janhaa diophantine equation
wazz it,
well i need an approach
i asked it to one of my faculty at coaching and he straightaway said it's wrong so i needed to check
P: 49
 Quote by janhaa I haven't the solution, I get the equation x + y = 130, where x and y are angles. If $x, y \in Z^+$ This is a diophantine equation. We know: x, y > 0. y > x. And y is greater than 90 degrees. the most probable angles: $x=20^o\,\, ,y=110^o$ or $x=30^o\,\, ,y=100^o$
 Quote by reenmachine I tried a couple of things but didn't solve it yet , but there's probably a way to build your way up to the x angle using the tricks in my sketch (just don't have the patience to construct the triangles properly and doing it now):
whatss y in equation
x+y= 130

reenmachine i agree myself i even not have patience and doing it (doing angle sum property question) , thanks for tip of parallel lines but what benefit it does
PF Gold
P: 520
 Quote by namanjain reenmachine i agree myself i even not have patience and doing it (doing angle sum property question) , thanks for tip of parallel lines but what benefit it does
I don't know since I didn't solve it.It was just a suggestion of strategy to attack the problem , maybe it's a dead end , but the parallel lines will at least allow you to chase more angles , whether or not they end up being useful to find angle x.

If you don't have the patience to try it , I suggest you do not ask others to do it for you as it's not recommended on the forum to ask for answers without showing that you tried hard before hand.I'm not a moderator , just friendly advice.Also , saying that you tried hard is not showing that you tried hard.
 P: 49 till here i ve done (in attchment) one of image is inverted so i did the mirror image from webcam toy Attached Thumbnails
 PF Gold P: 520 You should draw the triangles/angles to scale if you want to try that strategy. It should look like the picture below Attached Thumbnails
P: 49
 Quote by kingo1979 from the original figure below, y seems equal angle bde http://thinkzone.wlonk.com/mathfun/triangle.htm ===== where x + y + 50 = 180
however i got that but i also meant that diophtine (whatever is name) equation

well where is it taught
P: 49
 Quote by reenmachine you should draw the triangles/angles to scale if you want to try that strategy. It should look like the picture below
does that help, because doing any of olympiads we were never told to draw to scale and i was always of kind to do geometry of this kind mentally so it's quite difficult for me
though i think i'll print that page
 P: 49 Uff! After long work with a correct precise figure i bored and saw solution on one of other web pages is it bad of me not getting it (i'm 15 yrs and preparing rmo and iit)
PF Gold
P: 520
 Quote by namanjain does that help, because doing any of olympiads we were never told to draw to scale and i was always of kind to do geometry of this kind mentally so it's quite difficult for me though i think i'll print that page
I don't know , you should listen to your teachers before you listen to me that's for sure

You should also listen to mentors here as they are qualified to help you.
 PF Gold P: 520 Might try to prove both of these triangles (or another pair of triangles) are similar to prove x = 20 : Attached Thumbnails

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