Calculating Sphere Volume Using Trig Substitution

In summary, the problem requires finding the volume of a sphere of radius R by integrating over the primary volume elements in cartesian coordinates, using a trig substitution for the integral over dy. The equation for a sphere is R=sqrt(x^2+y^2+z^2). The limits for the integration are 0 to R for all coordinates.
  • #1
kristian321
2
0

Homework Statement



find the volume of a sphere of radius R by integrating over the primary volume elements in cartesian coordinates. Hint: use a trig substitution for your integral over dy

Homework Equations





The Attempt at a Solution



I don't understand what the problem wants me to do. I know equation of a sphere is R=sqrt(x^2+y^2+z^2) and maybe integrating will give me the volume. And if what would my limits be? Are they 0 to R for all?
 
Physics news on Phys.org
  • #2


kristian321 said:

Homework Statement



find the volume of a sphere of radius R by integrating over the primary volume elements in cartesian coordinates. Hint: use a trig substitution for your integral over dy

Homework Equations





The Attempt at a Solution



I know the limits for the integration. But I can't figure out what equation I'm supposed to integrate over
 

What is trig substitution?

Trig substitution is a technique used in calculus to solve integrals involving algebraic expressions and trigonometric functions. It involves substituting a variable with a trigonometric function to simplify the integral.

Why is trig substitution used to calculate the volume of a sphere?

Trig substitution is used to calculate the volume of a sphere because it allows us to simplify the integral and solve for the volume without needing to use more complex techniques. It is particularly useful when dealing with integrals involving square roots and trigonometric functions.

What is the formula for calculating the volume of a sphere using trig substitution?

The formula for calculating the volume of a sphere using trig substitution is V = 2π∫(a to b) (√(r^2-x^2))^2 dx, where r is the radius of the sphere and a and b are the limits of integration.

How does trig substitution work to calculate the volume of a sphere?

Trig substitution works by substituting the variable x with a trigonometric function, usually sin or cos, and then using trigonometric identities to simplify the integral. This allows us to solve for the volume of the sphere using basic calculus techniques.

What are some common mistakes to avoid when using trig substitution to calculate the volume of a sphere?

Some common mistakes to avoid when using trig substitution to calculate the volume of a sphere include forgetting to use the correct trigonometric identity, not choosing the appropriate substitution, and making errors when integrating. It is important to carefully follow the steps and double check your work to avoid these mistakes.

Similar threads

  • Calculus and Beyond Homework Help
Replies
9
Views
966
  • Calculus and Beyond Homework Help
Replies
8
Views
2K
  • Calculus and Beyond Homework Help
Replies
21
Views
2K
  • Calculus and Beyond Homework Help
Replies
3
Views
2K
  • Calculus and Beyond Homework Help
Replies
6
Views
1K
  • Calculus and Beyond Homework Help
Replies
7
Views
2K
  • Calculus and Beyond Homework Help
Replies
3
Views
2K
  • Calculus and Beyond Homework Help
Replies
7
Views
2K
  • Calculus and Beyond Homework Help
Replies
3
Views
950
  • Calculus and Beyond Homework Help
Replies
4
Views
1K
Back
Top