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Direction of Goldbach Partitions |
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| Aug6-12, 08:09 PM | #1 |
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Direction of Goldbach Partitions
I have been investigating goldbach partitions for some time.
One interesting observation I have been able to determine is concerning the "direction" of the goldbach partitions whether they are increasing or decreasing as 2N increases. To get an idea of this I constructed a function f(2N) where f(2N) = 1 if G[2N] - G[2N-2] > 0 f(2N) = 0 if G[2N] - G[2N-2] = 0 f(2N) = -1 if G[2N] - G[2N-2] < 0 where G[2N] is the number of partitions for the even number 2N. I then generated a sequence of numbers f(2N) begining at 2N = 10 and finishing at 2N=75398 [arbitrarily selected]. The sequence is then: {1,1,-1,1,1,-1,-1,1,1,-1,-1,1,-1,1,1,-1,1,1,-1,1,1,-1,-1,1,-1,1,1,-1,1,1,-1,.....} I ran a program to determine a histogram of the number of occurences of the subsequences of the following form histogram subsequence type No. of Occurences x,1,x 5563 x,-1,x 7003 x,1,1,x 7003 x,-1,-1,x 5562 x,1,1,1,x 0 x,-1,-1,-1,x 1 x,0,x 0 I have been trying to work out a descriptive name for this sequence. Any suggestions? The question then arises will a sequence generated from Hardy-Littlewoods equation for Goldbach partions be similar? Also , any comments on the histogram? Why the assymetric nature ? And why only these subsequences? I would have thought there would have been longer runs. Any ideas? Paul |
| Aug8-12, 01:15 AM | #2 |
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Recognitions:
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What exactly does 'x,1,x' mean? Are the two x's the same or independent? Either way, the count seems much too low. How can it be less than x,1,1,x?
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| Aug9-12, 05:27 AM | #3 |
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Hi Haruspex:
I am counting the number of consecutive runs of similar digits in the sequence. So the run x1x refers to either the subsequence 0,1,0, or 0,1,-1 or -1,1,0 or -1,1,-1. As another example the consecutive run of two positive ones viz x,1,1,x refers to the subsequences -1,1,1,0 or -1,1,1,-1 or 0,1,1,0 or 0,1,1,-1. All the counts are mutually exclusive, and add up to the correct number of digits [give or take one or two, as I am having problems with the start and end of the sequence] But the question remains why this particular pattern. Kind Regards Paul |
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