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Are polaritons simply photons propagating in medium? |
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| Nov21-12, 05:33 PM | #1 |
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Are polaritons simply photons propagating in medium?
In vacuum, the photon has a 4-momentum (E, p) with E^2 - p^2 = 0, i.e. it's massless. However, upon entering a medium of refractive index n, we expect that the photon retains its energy, while reducing its momentum by a factor n (due to increased wavelength). We then have for the 4-momentum of a photon in the medium (E, p/n) with E^2 - p^2 / n^2 != 0 which implies that the photon gains mass in a medium. Would it be correct to identify this particle not as a "photon in a medium" but as a polariton?
PS I'm a particle physicist, so take it easy on me :) Thanks! |
| Nov22-12, 01:57 AM | #2 |
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As long as n is constant, the photon (or polariton) will still be massless. However n will vary with frequency and wavevector, so that the polariton can gain an effective mass as m_eff=d^2E/dp^2.
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| Nov22-12, 07:59 AM | #3 |
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OK, so the question is, can I identify a polariton with a particle of energy E and momentum p/n?
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| Nov22-12, 08:45 AM | #4 |
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Are polaritons simply photons propagating in medium?However, strictly speaking a bare photon only describes the electromagnetic field in vacuum. The changes introduced by the medium can also always be described in terms of polaritons. Some fields use that stricter definition of what a polariton is. |
| Nov22-12, 09:26 AM | #5 |
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For my purposes, I need a word for a quasiparticle that represents a photon in an optical medium of refractive index n. That is, a particle that travels at the speed of c/n, carries energy E and momentum p/n, where E and p are energy and momentum of a photon with the same frequency propagating through vacuum. I am not particulary interested in the microscopic describtion of a medium or the strength of the coupling. All that matters it that light couples to matter and the information about the coupling is contained in one number: n. Would a "polariton" be a suitable word?
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| Nov22-12, 09:59 AM | #6 |
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I am not sure about the statements on momentum you make. Well defined is crystal or pseudo momentum which is not identical with the usual momentum. See my post #5 in this older thread:
http://www.physicsforums.com/showthr...ystal+momentum |
| Nov24-12, 07:50 PM | #7 |
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"Polaritons" have a dispersion curve consisting of two branches that are split by the coupling interactions. There is a forbidden gap in wavevector between the two branches. The boundaries of the gap are the frequencies of the transverse optical and longitudinal optical phonons. The dispersion curves of the polariton are very important in understanding the jargon. I am currently looking at Figure 11 on page 287 of the following reference: "Introduction to Solid State Physics" 7th edition by Charles Kittel (Wiley, 1996). A "photon-like polariton" is not really the same as a photon. Strictly speaking, a true photon can exist only in a vacuum. However, the word "photon" is often applied to those excitations in a solid that travel at a phase velocity of "c/n", where "c" is the speed of light in a vacuum and "n" is the index of refraction. The velocity of light in a solid is really the speed of the photon-like polariton in a vacuum. Similarly, the "optical phonons" in a solid are really "phonon-like" polaritons. The dispersion curves of the uncoupled phonon and the uncoupled photon cross. The branches are split at the point of crossing. Near the forbidden gap, polaritons have a mixed phonon-photon nature. |
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