Parallel plate capacitor with a dielectric?

In summary, the capacitor voltage is always the same as the emf, so you can use that to find the electric displacement field. The electric displacement field is independent of the dielectric, so you can find it for each part of the space.
  • #1
basenne
20
0
If you have a simple circuit with only a battery and a parallel plate capacitor with a dielectric, what exactly happens when the battery is turned on?

Also, if the voltage of a capacitor with a dielectric is less than the EMF of the battery, what happens to the rest of the voltage?

One last question... if the dielectric doesn't fill the space between the parallel plates, how does one calculate the electric field strength in the gap in between a plate and the dielectric? I know that you'd use Gauss's law and find that E = Q/(ε*A)... but how would you find Q? Would you use Q=CV? If so, would you use the EMF of the battery or the voltage of the capacitor?

Thanks, as always for all your help.
 
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  • #2
hi basenne! :smile:
basenne said:
If you have a simple circuit with only a battery and a parallel plate capacitor with a dielectric, what exactly happens when the battery is turned on?

the battery starts "pushing" charge onto one plate of the capacitor, and "pulling" charge off the other plate

eventually, the voltage across the capacitor is the same as the emf
Also, if the voltage of a capacitor with a dielectric is less than the EMF of the battery, what happens to the rest of the voltage?

do you mean the breakdown voltage of the capacitor?

if the emf exceeds the breakdown voltage, then sparks will pass across the middle of the capacitor

if the emf doesn't exceed the breakdown, then the capacitor voltage is always the same as the emf (eventually)
if the dielectric doesn't fill the space between the parallel plates, how does one calculate the electric field strength in the gap in between a plate and the dielectric? I know that you'd use Gauss's law and find that E = Q/(ε*A)... but how would you find Q? Would you use Q=CV? If so, would you use the EMF of the battery or the voltage of the capacitor?

the capacitor voltage is the same as the emf

so use that to find D (the electric displacement field) …

D is independent of the dielectric

then find E from D, for each part of the space :smile:
 
  • #3
That really cleared up my questions.

Thanks a lot!
 

1. What is a parallel plate capacitor with a dielectric?

A parallel plate capacitor with a dielectric is a device that is used to store electrical energy. It consists of two conductive plates separated by a non-conductive material called a dielectric.

2. How does a parallel plate capacitor with a dielectric work?

When a voltage is applied to the capacitor, an electric field is created between the plates. The dielectric material between the plates increases the capacitance of the capacitor, allowing it to store more charge and therefore more energy.

3. What are some common dielectric materials used in parallel plate capacitors?

Some common dielectric materials used in parallel plate capacitors include air, paper, mica, glass, and various types of plastics. The choice of dielectric material depends on the specific application and the desired properties of the capacitor.

4. What are the advantages of using a dielectric in a parallel plate capacitor?

The use of a dielectric in a parallel plate capacitor allows for a higher capacitance, which means that the capacitor can store more charge and energy. It also helps to reduce the electric field between the plates, making the capacitor more stable and less likely to break down.

5. How do you calculate the capacitance of a parallel plate capacitor with a dielectric?

The capacitance of a parallel plate capacitor with a dielectric can be calculated using the formula C = εA/d, where C is the capacitance, ε is the permittivity of the dielectric material, A is the area of the plates, and d is the distance between the plates. The permittivity of the dielectric can be found in tables or can be calculated using the dielectric constant of the material and the permittivity of free space.

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