Lorentz transformation of delta functionby Chenkb Tags: delta, delta function, function, lorentz, lorentz boost, transformation 

#1
Feb814, 03:11 AM

P: 19

For two body decay, in CM frame, we know that the magnitude of the final particle momentum is a constant, which can be described by a delta function, ##\delta(\vec{p^*}\vec{p_0^*})##, ##\vec{p_0^*}## is a constant.
When we go to lab frame (boost in z direction), what's the Lorentz transformation of the delta function? regards! 



#2
Feb814, 03:10 PM

P: 263

What do you mean by "which can be described by a delta function" ?




#3
Feb814, 07:37 PM

P: 19

Maybe my example of two body decay is not so suitable, but my question is just for mathematics, that is the Lorentz transformation of ##\delta(\vec{p}\vec{p_0^*})## 



#4
Feb914, 07:53 AM

Sci Advisor
Thanks
P: 3,856

Lorentz transformation of delta function 



#5
Feb1014, 03:35 AM

P: 263

Chenkb,
Are talking about a distribution function in the momentum space, and about how this function might evolve with an interaction? Are you considering 3momentum or 4momentum? 


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