- #1
Feynmanfan
- 129
- 0
Dear friends,
I need some help with this problem.
"What is the probability of building a solvable rubik cube only by ordering randomly all pieces but three"(let us suposse that these 3 pieces are vertices)
That is you first get a random cube without three vertices and then you try to build a solvable cube by choosing a correct position for these three vertices.
What I got is that only 1/12 of all posible random cubes are solvable. I think that all posible random configurations are 8!*3^8*12!*2^8. But the thing is that in this problem 3 vertices are correctly places. I don't know what to do.
Thanks for your help
I need some help with this problem.
"What is the probability of building a solvable rubik cube only by ordering randomly all pieces but three"(let us suposse that these 3 pieces are vertices)
That is you first get a random cube without three vertices and then you try to build a solvable cube by choosing a correct position for these three vertices.
What I got is that only 1/12 of all posible random cubes are solvable. I think that all posible random configurations are 8!*3^8*12!*2^8. But the thing is that in this problem 3 vertices are correctly places. I don't know what to do.
Thanks for your help