Mv=mv conservation of momentum

In summary, two people are standing on a balanced board, with one person jumping up at 1.5m/s. The other person is asked how fast they will be moving just after the jump. The concept of conservation of angular momentum is introduced and used to determine the second person's speed. The total angular momentum of the system remains zero, and by considering the angular momentum of the first person, it can be deduced that the second person's speed will be non-zero unless the board does not rotate.
  • #1
Kchu
4
0
i don't know how to solve this problem is it a conservation of momentum problem?

because can't you just use

mv=mv?
 

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  • #2
What exactly is the problem?
 
  • #3
oops! =]

**Two people are standing on a very light board that is balanced on a fulcrum. The lighter person suddenly jumps straight up at 1.5m/s
Just after he jumps, how fast will the heavier person be moving?**
 
  • #4
Consider conservation of angular momentum.
 
  • #5
mrv=mrv but it doesn't rotate?
 
  • #6
Assuming you mean that to be [itex]m_1 r_1 v_1 = m_2 r_2 v_2[/itex], then that is correct. What makes you think it doesn't rotate? (If the board doesn't rotate, the second man would have speed = 0.)

A bit more explanation may help.

The total angular momentum of the system about the fulcrum is conserved. It starts out at zero before the man jumps and remains at zero after the man jumps. The system consists of both men and the board. (Since the board is light, we can ignore its mass and angular momentum.)

What is the angular momentum of the man after he jumps? Then what must be the angular momentum of the other man? (Don't forget that angular momentum has an orientation; think clockwise versus counterclockwise.) Use that to figure out the second man's speed.
 

What is the principle of conservation of momentum in physics?

The principle of conservation of momentum states that the total momentum of a closed system remains constant. This means that in a system where there are no external forces acting, the total momentum before and after an interaction remains the same.

How is the equation "Mv=mv conservation of momentum" derived?

The equation "Mv=mv conservation of momentum" is derived from the principle of conservation of momentum. It is based on the fact that the total momentum of a system before and after an interaction must be equal. This equation represents the conservation of momentum in terms of mass and velocity.

What is the difference between elastic and inelastic collisions in terms of "Mv=mv conservation of momentum"?

In an elastic collision, the total kinetic energy and momentum of the system are conserved. This means that both "Mv" and "mv" will remain the same before and after the collision. In an inelastic collision, however, some of the kinetic energy is converted into other forms of energy, such as heat or sound, and the total kinetic energy of the system is not conserved. Therefore, in an inelastic collision, "Mv" and "mv" may not remain the same before and after the collision.

How does the law of conservation of momentum apply in real-life scenarios?

The law of conservation of momentum is applicable in various real-life scenarios, such as a ball bouncing off a wall or two objects colliding. It is also applied in sports, such as billiards or bowling, where the momentum of the objects involved must be conserved for the game to be played correctly.

What are some limitations of "Mv=mv conservation of momentum"?

One limitation of the "Mv=mv conservation of momentum" equation is that it only applies to closed systems where there are no external forces acting. In real-life scenarios, it is challenging to have a perfectly closed system, so the equation may not be entirely accurate. Additionally, the equation only applies to objects moving in a straight line, and it does not account for rotational motion or other factors such as friction.

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