New Reply

question on center of mass (centroid)

 
Share Thread
Sep16-12, 11:09 AM   #1
 

question on center of mass (centroid)


Hello,

I was thinking of the following question: suppose we have a body in two-dimensional space and its density is described by the function [itex]f(x,y)[/itex] (Note! in Cartesian coordinates!). The x-coordinate of the center of mass is given by [tex]C_x= \frac{\int\int xf(x,y)dxdy}{\int\int f(x,y)dxdy}[/tex] where the domain of integration is ℝ2. The y-coordinate of the center of mass is given by an analogous formula.

Now, suppose we are given the density of this body in polar coordinates, that is: f(r,θ). Is it possible to obtain directly the centroid [itex](C_r, C_\theta)[/itex] in polar coordinates from f(r,θ)?

Of course I know that by using a polar-to-Cartesian curvilinear transformation x=x(r,θ), y=y(r,θ), we can easily obtain the formulas [itex]C_x(r,\theta)[/itex] and [itex]C_y(r,\theta)[/itex], and then we could just convert Cx and Cy into polar coordinates. However if you think about it, when we calculate [itex]C_x(r,\theta)[/itex] and [itex]C_y(r,\theta)[/itex] we are essentially calculating the Cartesian coordinates of the center of mass.

Can we "bypass" this step? What's so special here with Cartesian coordinates? Aren't we supposed to be able to calculate the center of mass of a body without resorting to a special coordinate system?
PhysOrg.com physics news on PhysOrg.com

>> Cheap, color, holographic video: Better holographic video displays
>> First entanglement between light and optical atomic coherence
>> EUROnu project recommends building Neutrino Factory
Sep16-12, 01:32 PM   #2
 
Recognitions:
Homework Helper Homework Help
Yes you can bypass the step and do the calculation entirely in polar coordinates.
http://www.physicsforums.com/showthread.php?t=496083
Sep16-12, 02:28 PM   #3
 
Hi Simon,
I read the thread that you cited in your post. I believe the user who posted that question was essentially posing the same question as mine, but actually he did not get an answer.

I did not see any post in that thread with anyone suggesting how to "bypass" the cartesian coordinates and obtain directly the centroid in polar coordinates (Cr, Cθ) by integrations of f(r,θ).

In that thread, to the question "Are there integrals that give r-bar and theta-bar?", Mark44 replied: There might be, but I don't recall ever seeing any.

At the current state of things, it seems to me that the concept of "center of mass" was defined in cartesian coordinates. Once we have that definition we can obviously find the centroid in any other coordinate system. However I wonder if it is possible to define the "center of mass" in a coordinate-free manner (if that makes sense), or at least to give a (physically) consistent definition without using the cartesian coordinates as a starting point.

EDIT: I noticed that Wikipedia has a "coordinate-free" definition of center of mass for continuous distributions
Sep16-12, 03:10 PM   #4
 
Recognitions:
Homework Helper Homework Help

question on center of mass (centroid)


Ah - I should have read more carefully.
Yes - the coordinates are just a way of describing positions and the com is just a position.
To work out how to do it in polar coords, you need to understand what the center of mass actually is... what you are doing when you do the integration.
New Reply

Similar discussions for: question on center of mass (centroid)
Thread Forum Replies
Moments,Center of Mass, & Centroid Calculus & Beyond Homework 1
center of mass of semicirculardisk calculated from center of mass of semicircular arc Introductory Physics Homework 5
How do I locate the centroid and the center of gravity of a square pyramid? Introductory Physics Homework 6
Centroid ("center of mass") of cardioid... revisited Calculus & Beyond Homework 1
centroid ("center of mass") of cardioid Calculus & Beyond Homework 3