- #1
almondsize
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Hi everyone. I'm kind of new here, please be nice.
So I was reading up some physics and came across the fact that if the no. of neutrons is too high compared to the no. of protons, the nucleus becomes unstable. I can understand why this happens with protons, due to the coloumbic repulsion between the charged protons, but I don't understand why this happens with neutrons. I tried googling it and the best explanation I got was "because of the nuclear force". I know what the nuclear/strong force is (well, at a high school level), which is exactly why I'm asking this question.
Neutrons, without any charge, is a mean to hold the nucleus together despite the strong electric force, by its nuclear force. Nuclear force holds the protons together, because in very small distances, smaller than the diameter of the nucleons, it overpowers the electric force, thus acts like cement linking the protons together.
But, let's say we have a fairly large but stable nucleus, like iron, and we throw in a few neutrons. The neutrons should not affect the nucleus in a negative way, as the only force it can interact with the neutron with, is the strong force, which is attractive. (Well, it's repulsive for very, very small distances, but all this does is keep the nucleons at a stable distance from each other, and makes sure they aren't a "continuous mass") It'd be just like adding more glue.
But, clearly this isn't the case. It'd be great if someone could help me out here, by either proving my logic wrong, or giving me more information on how the nuclear force works.
I hate high school physics sometimes. It just makes you assume stuff without explaining how each components works. And then, later, in a test, it asks you to "explain". It's almost like asking me to write an essay on how E=mc^2 is derived, when the only thing they've given me is the equation.
Sorry about my complaint/rambling, at the end there :P Thanks
So I was reading up some physics and came across the fact that if the no. of neutrons is too high compared to the no. of protons, the nucleus becomes unstable. I can understand why this happens with protons, due to the coloumbic repulsion between the charged protons, but I don't understand why this happens with neutrons. I tried googling it and the best explanation I got was "because of the nuclear force". I know what the nuclear/strong force is (well, at a high school level), which is exactly why I'm asking this question.
Neutrons, without any charge, is a mean to hold the nucleus together despite the strong electric force, by its nuclear force. Nuclear force holds the protons together, because in very small distances, smaller than the diameter of the nucleons, it overpowers the electric force, thus acts like cement linking the protons together.
But, let's say we have a fairly large but stable nucleus, like iron, and we throw in a few neutrons. The neutrons should not affect the nucleus in a negative way, as the only force it can interact with the neutron with, is the strong force, which is attractive. (Well, it's repulsive for very, very small distances, but all this does is keep the nucleons at a stable distance from each other, and makes sure they aren't a "continuous mass") It'd be just like adding more glue.
But, clearly this isn't the case. It'd be great if someone could help me out here, by either proving my logic wrong, or giving me more information on how the nuclear force works.
I hate high school physics sometimes. It just makes you assume stuff without explaining how each components works. And then, later, in a test, it asks you to "explain". It's almost like asking me to write an essay on how E=mc^2 is derived, when the only thing they've given me is the equation.
Sorry about my complaint/rambling, at the end there :P Thanks