- #1
beginner16
- 51
- 0
hello
Suppose there is no friction between the car and the road -> if car is on a banked turn , the normal force ( which is always perpendicular to the road's surface ) is no longer vertical . The normal force now has a horizontal component , and this component can act as the centripetal force on the car
But doesn't gravity force have a component that is of equal size , but in opposite direction than normal force ? In which case net force pulling on car would be zero and thus couldn't act as centripetal force ?
So how can net force equal horizontal component of normal force ?
Also , what must be angles between the components of normal force and how are they related to the banking angle between the road and the horizontal ?
thank you
Suppose there is no friction between the car and the road -> if car is on a banked turn , the normal force ( which is always perpendicular to the road's surface ) is no longer vertical . The normal force now has a horizontal component , and this component can act as the centripetal force on the car
But doesn't gravity force have a component that is of equal size , but in opposite direction than normal force ? In which case net force pulling on car would be zero and thus couldn't act as centripetal force ?
So how can net force equal horizontal component of normal force ?
Also , what must be angles between the components of normal force and how are they related to the banking angle between the road and the horizontal ?
thank you