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hardwork
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PART 1: Unpolarized light has an intensity of 100 W/m^2. It passes though a polarizer whose transmission axis is rotated 18 degrees with respect to the vertical. What is the intensity of the light that emerges from the polarizer?
I = (1/2)(Io)(cos angle)^2
I = (1/2)(100 W/m^2)(cos 18)^2
I = 45 W/m^2 -- I am not sure if this is correct.
PART 2: This light passes through a second polarizer and the intensity of the light that emerges is 40 W/m^2. What angel does the transmission axis of the second polarizer make with the vertical?
I don't understand this part. Would I use the same equation above and plug in 40 W/m^2 for I, 100 W/m^2 for Io, and solve for cos?
Thank you!
I = (1/2)(Io)(cos angle)^2
I = (1/2)(100 W/m^2)(cos 18)^2
I = 45 W/m^2 -- I am not sure if this is correct.
PART 2: This light passes through a second polarizer and the intensity of the light that emerges is 40 W/m^2. What angel does the transmission axis of the second polarizer make with the vertical?
I don't understand this part. Would I use the same equation above and plug in 40 W/m^2 for I, 100 W/m^2 for Io, and solve for cos?
Thank you!