Do you know this formula?

[micromass]

Do you know this formula??

Let's try to make a little game out of scientific formulas. The idea is that I post a scientific formula which is named after a famous scientist. The goal is to guess the scientist(s) associated with the formula.

The person who answers correctly, gets to present a new formula. Etc.

So let's start easy:

$$\sigma(x)\sigma(p)\geq \frac{\hbar}{2}$$

 

[kevinferreira]

Let's try to make a little game out of scientific formulas. The idea is that I post a scientific formula which is named after a famous scientist. The goal is to guess the scientist(s) associated with the formula.

The person who answers correctly, gets to present a new formula. Etc.

So let's start easy:

$$\sigma(x)\sigma(p)\geq \frac{\hbar}{2}$$

Heisenberg!

 

[micromass]

Heisenberg!

Of course!

You can put up a new formula if you want!

 

[kevinferreira]

Ok, here it goes a nice (but long) one, with a nice name too:

$$\frac{d}{dt}P_{m\rightarrow n}(t)=2\pi |\langle n|H_{int}|m\rangle |^2 \rho(E)$$

 

[jtbell]

Would that be Fermi's Golden Rule?

Here's one that's perhaps not so famous, but has a name that makes me smile when I see it:

$$\frac {n^2 - 1}{n^2 + 2} = \frac{4 \pi}{3} N \alpha$$

Hint: it's named after two people whose names are very very similar.

 

[George Jones]

So let's start easy

I was uncertain, but I thought you might be looking for a deviation from standard nomenclature.

 

[Dr Transport]

Would that be Fermi's Golden Rule?

Here's one that's perhaps not so famous, but has a name that makes me smile when I see it:

$$\frac {n^2 - 1}{n^2 + 2} = \frac{4 \pi}{3} N \alpha$$

Hint: it's named after two people whose names are very very similar.

Clausius-Mossotti?

How about this:
$$ \left\langle \alpha' j'm'|T^{(k)}_{q}|\alpha j m \right\rangle = \frac{\left\langle \alpha' j'||T^{(k)}||\alpha j \right\rangle}{\sqrt{2j'+1}}\left\langle kjqm|kjj'm'\right\rangle $$

 

[jtbell]

Clausius-Mossotti?

That's one name for it, but not the name I was thinking of.

 

[micromass]

That's one name for it, but not the name I was thinking of.

Lorentz-Lorenz equation?

No idea about Dr Transport his formula though...

 

[Dr Transport]

Lorentz-Lorenz equation?

No idea about Dr Transport his formula though...

hint: one of the people this formula is named for wrote a very well known group theory book

 

[George Jones]

$$ \left\langle \alpha' j'm'|T^{(k)}_{q}|\alpha j m \right\rangle = \frac{\left\langle \alpha' j'||T^{(k)}||\alpha j \right\rangle}{\sqrt{2j'+1}}\left\langle kjqm|kjj'm'\right\rangle $$

Wigner-Eckart Theorem.

I recognized this as soon as I saw it, but I have been too lazy to think of my own puzzle.

 

[George Jones]

Okay,

$$\int \liminf_{n\rightarrow +\infty} |f_n| d\mu\leq \liminf_{n\rightarrow +\infty} \int |f_n|d\mu$$

Thanks, micromass.

 

[mathwonk]

Fatou's lemma.chi(L) = [e^(ch(L)).Todd(X)](dim(X)). (3 names)Here's a rather obscure one physics students of Paul Bamberg at Harvard in the 1960's all knew:

617-495-9560 (Bamberg's number)

 

[mathwonk]

Wannabe: I just noticed you have to answer the previous one to get to post a question.

 

[WannabeNewton]

Wannabe: I just noticed you have to answer the previous one to get to post a question.

Oh, well in that case I have no idea what your formula is lol...Newton's 2nd law is out of the question innit :)? (I deleted my post by the way)

EDIT: is it the Hirzebruch–Riemann–Roch theorem?

 

[mathwonk]

yes! (I got it wrong myself, thinking it was Grothendieck Riemann Roch.)

 

[WannabeNewton]

Yay! Ok mine will still be $\xi_{[a}\nabla_{b]}\kappa = 0$

 

[PhizKid]

Yay! Ok mine will still be $\xi_{[a}\nabla_{b]}\kappa = 0$

zeroth law of black hole thermodynamics

$E = -\lim_{S_{\alpha}\rightarrow \mathcal{P}}\frac{1}{8\pi}\int _{S_{\alpha}}\epsilon_{abcd}\nabla^{c}\xi^{d}$

 

[AnTiFreeze3]

$E = -\lim_{S_{\alpha}\rightarrow \mathcal{P}}\frac{1}{8\pi}\int _{S_{\alpha}}\epsilon_{abcd}\nabla^{c}\xi^{d}$

Why, that's the good ol' Bondi energy, of course!

Here's mine: $y=mx+b$

 

[WannabeNewton]

Here's mine: $y=mx+b$

Is this the Noetherian current obtained from Lorentz transformations? Seems like it.

 

[AnTiFreeze3]

Is this the Noetherian current obtained from Lorentz transformations? Seems like it.

You're getting close!