3DOF Reentry Trajectory Equations of motion

In summary: It sounds like you've corrected your range equation. Can you please numerically integrate the equations to see if the new values produce a more realistic trajectory?
  • #1
roldy
237
2
I'm working on a project for myself in regards to atmospheric reentry. I've come across some equations that describe the reentry trajectory. I decided to derive the equations using the diagram shown in the attached picture. Are these correct? The reason why I'm asking is that I'm getting small values for [itex]\phi[/itex] which is the angular displacement (range). I'm numerically integrating these equations. I've included plots from my program for altitude vs range and altitude vs velocity.

For this test I'm using the following initial values:
α = 35°
S = 12.97 m2
g = 9.815(R/(R + alt))2 m/s2
ρ = 1.752e-alt/6700 kg/m3
m = 3855.54 kg
θ = 0°
V = 750 m/s
alt = 120000 m
[itex]\phi[/itex] = 0°
time step size dt = 0.1

[itex]C_L = 2\sin^2\alpha \cos \alpha[/itex]
[itex]C_D = 2\sin^3\alpha[/itex]
[itex]L = 1/2C_d \rho V^2 S[/itex]
[itex]D = 1/2C_d \rho V^2 S[/itex]
[itex]\dot{V} = -D/m - g\sin\theta[/itex]
[itex]\dot{\phi} = V\cos\theta/(R + alt)[/itex]
[itex]\dot{\theta} = (L/m - g\cos\theta)/V - \dot{\phi}[/itex]
[itex]\dot{alt} = -V\cos\theta[/itex]
 

Attachments

  • Untitled-1.jpg
    Untitled-1.jpg
    14.8 KB · Views: 736
  • alt vs range.jpg
    alt vs range.jpg
    13.2 KB · Views: 697
  • alt vs vel.jpg
    alt vs vel.jpg
    11.2 KB · Views: 450
Physics news on Phys.org
  • #2
Hi roldy, good on you for working on your atmospheric reentry project just for fun ;)

It is difficult to assess whether or not your results are 'correct' without seeing how your code fits all the equations together.

Just as an outside observer to your results, your graphs are saying that the spacecraft s descends with a constant gradient. So in other words, for any change in velocity in the normal direction (altitude), there is a correspondingly proportionate change in the tangential direction (range).

This would mean that the resultant force vector (from adding lift, drag, gravity etc.) is always at a particular angle to the spacecraft (if using an n-t coordinate system). Does this sounds like a realistic scenario?

From your velocity graph it looks like your spacecraft can land safely after all!

Have a good think through it and I'm sure you can solve it. :)
 
Last edited:
  • #3
Reentry program

The linear relationship of altitude to range leads me to believe that something is wrong with the range equation since the other plots of altitude vs velocity and altitude vs time look accurate. I've attached a zip file of the code I've developed thus far.

I've commented out some stuff intended to be used for actually finding the limits for the reentry corridor since I'm trying to figure out this range problem. Error while loop ends if the pilot penalty function (some function that adds up the total g-force loading on the pilot) is >= 1. I have an altitude penalty function setup for later if the capsule skips out which will be developed more later. ReentryCorr.m is the main program.

I've been trying for a couple days now on this problem.

Note: I believe that [itex]\phi[/itex] should be

[itex]\phi = V\sin \theta /(R + alt)[/itex]

and if I delete [itex]\phi[/itex] from the [itex]\dot{\theta}[/itex] equation I don't get a linear plot. However the order of magnitude for [itex]\phi[/itex] is 10-4.
 

Attachments

  • Reentry.zip
    2.1 KB · Views: 265
Last edited:
  • #4
Thanks for posting your code.
Did you derive the system equations or are they from someone's text?

Perhaps your trig ratios for Vdot and Theta dot should be:

[itex]\dot{V} = -D/m - g\cos\theta[/itex]
[itex]\dot{\theta} = (L/m - g\sin\theta)/V - \dot{\phi}[/itex] ?

I've briefly tested your code with the above change but am not convinced it gives any better results.
Let me know how you go.

It sounds like your model has some interesting things to come :)
 
  • #5
I derived them myself at first to fully understand how they came to be. I then checked in other sources. One of them is from the attached document on page 11. I've been trying to search for an example that has data with it so I can compare my plots and values.
 

Attachments

  • AP-lec4.pdf
    758.5 KB · Views: 2,931
  • #6
I think I might of figure it out. I decided to move theta on the other side of the velocity vector and change the equations around to reflect this change. For the range I set up a ratio to find the angle. Vcosθ gives me the tangential distance. The ratio I set up is as follows.

[itex] \frac{2\pi(R + alt)}{360} = \frac{V\cos \theta}{\phi}[/itex]

And I solve for [itex] \phi[/itex]. I now get a correct order of magnitude. However, the plot is still linear-like. I should note that the plot is not entirely linear; I went into photoshop and dropped a line from endpoint to endpoint and the plot sagged below the line.

I've attached the new trajectory diagram and a plot of the range.
 

Attachments

  • Untitled-1.jpg
    Untitled-1.jpg
    14.5 KB · Views: 566
  • range.jpg
    range.jpg
    11.7 KB · Views: 576
  • #7
Still not entirely sure about my correction since every document or website I come across has V*[itex]\cos \theta[/itex]/(R + alt).
 
  • #8
roldy can u please solve the 2 DOF equation of motion for reentry vehicle and numercally integrate it by euler integration or runge kutta 4 ODE
 
  • #9
Rd123, is this a question in regards to helping solve my problem or is this something that you are halving problems with?
 
  • #10
ya roldy i am little bit confused ,,,the first thing is that
1) derive the 2 DOF equations of motions for an reentry vehicle?
2)Numerically integrate the above equations of motions to obtain the trajectory of a reentry vehicle having following conditions:mass=3000kg
flight path angle=-2 deg
velocity=7908 m/s
phi=0 deg
radius (r) = 100 km above the surface of earth
surface area (s)=6 m^2
Cd=1.1
L/D= any choice
so basically i have to numerically integrate that by euler or runge kutta 4 order ODE method ,,,, so i am stuck and don't know how to write that MATLAB code,,,please "roldy" help me out to solve it ...
Or if you could solve it ...it would be great helpful to me ,,,,,,
 
  • #11
Upon re-reading my original post and the equations, the equations presented can be used for the 2 DOF equations. In my case I just didn't use the 3rd dimension to describe translational movement.

I would approach coding this problem as follows:

1. Define reentry parameters
2. Define differential equation to be used in Runge-Kutta Method. This should replace the equation f = @(theta) -2.2067e-12*(theta(1,1)^4-81e8). Do some research on this and try to see which differential equation you should use. My initial guess would be a differential equation in involving velocity.
3. You will need to change the FOR loop to a WHILE loop because you do not know the end time. You could do something like
WHILE altitude > 0
...
end

I attached some code on the Runge-Kutta Method for heat loss and the pdf describing the problem.
 

Attachments

  • Runge_Kutta.m
    786 bytes · Views: 509
  • mws_gen_ode_txt_runge4th.pdf
    968.6 KB · Views: 380
  • #12
roldy ,,i hope it surely will help me ,,but in the mean time ,please can you post any link for the MATLAB coding of the trajectory equations,, needed to find various parameters...
 

What is a 3DOF Reentry Trajectory?

A 3DOF (3 degrees of freedom) reentry trajectory refers to the motion of a spacecraft or object as it enters the Earth's atmosphere. It takes into account three main variables: velocity, altitude, and flight path angle.

How are the Equations of Motion for a 3DOF Reentry Trajectory derived?

The Equations of Motion for a 3DOF Reentry Trajectory are derived from the principles of dynamics and aerodynamics, including Newton's laws of motion, the law of conservation of energy, and the laws of thermodynamics.

What factors affect the accuracy of the 3DOF Reentry Trajectory Equations of Motion?

The accuracy of the 3DOF Reentry Trajectory Equations of Motion is affected by various factors such as atmospheric conditions, spacecraft design and characteristics, and the complexity of the trajectory (e.g. maneuvers or atmospheric disturbances).

What are the limitations of the 3DOF Reentry Trajectory Equations of Motion?

The 3DOF Reentry Trajectory Equations of Motion have limitations in accurately predicting the trajectory of a spacecraft in certain scenarios, such as extreme atmospheric conditions, unexpected disturbances, or when the spacecraft deviates from its intended trajectory.

How are the 3DOF Reentry Trajectory Equations of Motion used in real-world applications?

The 3DOF Reentry Trajectory Equations of Motion are used in real-world applications, such as spacecraft design and reentry planning, to predict and analyze the behavior of a spacecraft during its reentry into the Earth's atmosphere. They are also used in simulators and models for training and testing purposes.

Similar threads

Replies
2
Views
864
Replies
76
Views
4K
Replies
2
Views
4K
Replies
9
Views
1K
Replies
7
Views
937
Replies
4
Views
2K
  • Advanced Physics Homework Help
Replies
6
Views
624
  • Introductory Physics Homework Help
3
Replies
73
Views
841
Replies
6
Views
974
Back
Top