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Angular acceleration and centri fugal/petal Force...

by PhysicsStudnt
Tags: acceleration, angular, centri, force, fugal or petal
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PhysicsStudnt
#1
Jul24-14, 06:11 PM
P: 18
Experts,

I need to find out the centrifugal acceleration on a ball of mass m placed at a distance R from one end of the rod, and that end is being pivoted to rotate the rod..Of angular acceleration is alpha, is it correct to say,

Centripetal / centrifugal (in case that the ball remains stationary at the point) = R* (alpha) * M

On calculating the tangential force on the ball, i see a result, F(tangential) = M * R *(alpha)

I strongly feel that, the tangential force that we obtain on viewing the system from an external stationary reference frame, should be exactly same as the centrifugal force when we view it being in the rotating frame. Since i feel that both of the tangential force and the centrifugal force create the same influence but in different frames...

I need a more authentic explanation to it...could someone please explain...
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NascentOxygen
#2
Jul25-14, 05:15 AM
HW Helper
Thanks
P: 5,497
You wrote "angular acceleration is alpha". Do you mean angular velocity?
A.T.
#3
Jul25-14, 08:02 AM
P: 4,246
The inertial effects of angular acceleration of the reference frame are called Euler force, which adds to the effects of the angular velocity of the reference frame (centrifugal, Coriolis):

http://en.wikipedia.org/wiki/Euler_force

Quote Quote by PhysicsStudnt
I strongly feel that, the tangential force that we obtain on viewing the system from an external stationary reference frame,
If the system has angular acceleration in an inertial frame, then there must a real tangential force that exists in every frame. In the angularly accelerating restframe of the system this real tangential force is balanced by the Euler force.


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