- #1
Physics103
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A satellite orbits Earth with T= 5.1 x 10^3 s. What is the value for g at this point.
some constants i found:
Mass of Earth = 5.98 x 10^24lg
r of Earth = 6.38 x10^6m
I realize that because the T is pretty small that the value for g will be close to 9.8. This is what i can think of
Gmemo / r^2 = mg
Gme / r^2 = g
and
Fc = mo4pie^2r / T^2
Since Fc = Fg
mg = mo4pie^2r / T^2
thus g = 4pie^2r / T^2
i tried subbing the equations together to get r and from that get g but it seems to me like I am doing it wrong. Its only a multiple choice problem so i don't see why it would be so complicated (if infact its done they i showed).
Thank for any help
some constants i found:
Mass of Earth = 5.98 x 10^24lg
r of Earth = 6.38 x10^6m
I realize that because the T is pretty small that the value for g will be close to 9.8. This is what i can think of
Gmemo / r^2 = mg
Gme / r^2 = g
and
Fc = mo4pie^2r / T^2
Since Fc = Fg
mg = mo4pie^2r / T^2
thus g = 4pie^2r / T^2
i tried subbing the equations together to get r and from that get g but it seems to me like I am doing it wrong. Its only a multiple choice problem so i don't see why it would be so complicated (if infact its done they i showed).
Thank for any help