Lagrangian mechanics of a bead of mass

In summary, a bead of mass m constrained to move on a frictionless wire helix can be described using the distance s along the helix as the generalized coordinate. The Lagrangian for this system is given by L = T - V, where T is the kinetic energy and V is the potential energy. The force acting on the bead depends only on the magnitude of the distance from the center of the helix. The distance s can be calculated using the formula s = \phi\sqrt{a^2+z^2}.
  • #1
stunner5000pt
1,461
2
consider a bead of mass m constrained to move on a fricitonless wire helix whose equations in cylindrical polar coords is
z = a phi where a is some constant
the bead is acted upon by a force which deends on the distance from the cneter only.
Formulate the problem using s the distance along the helix as your generalized coordinate.

for distance s along the helix [itex] s = a \phi_{0} [/itex]
but r would not be constnat
[tex] T = \frac{1}{2} m (\dot{r}^2 + r^2 \dot{\phi_{0}}^2 + \dot{z}^2) [/tex]
z dot is zero and phi0 is a constnat soso
[tex] T = \frac{1}{2} m \dot{r}^2 [/tex]


the force is dependant on the distance from the center only
thus [tex] \vec{F} = -k\vec{r} = -\nabla V [/tex](say)
then [tex] V = \frac{1}{2} k (r^2 + z^2) = \frac{1}{2} k (r^2 + z^2) = \frac{1}{2} k (r^2 + a^2 \phi_{0}^2) [/tex]
[tex] L = T - V = \frac{1}{2} m\dot{r}^2- \frac{1}{2} k (r^2 + a^2 \phi_{0}^2) [/tex]
is this formulation correct?
Or am i totally off?
 
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  • #2
First question...Why doesn't "s" denote the generalized coordinate in the lagrangian...?

L should be [itex] L\left(s,\dot{s}\right) [/itex]...

Daniel.
 
  • #3
stunner5000pt said:
consider a bead of mass m constrained to move on a fricitonless wire helix whose equations in cylindrical polar coords is
z = a phi where a is some constant
the bead is acted upon by a force which deends on the distance from the cneter only.
Formulate the problem using s the distance along the helix as your generalized coordinate.

for distance s along the helix [itex] s = a \phi_{0} [/itex]
but r would not be constnat
[tex] T = \frac{1}{2} m (\dot{r}^2 + r^2 \dot{\phi_{0}}^2 + \dot{z}^2) [/tex]
z dot is zero and phi0 is a constnat soso
[tex] T = \frac{1}{2} m \dot{r}^2 [/tex]
the force is dependant on the distance from the center only
thus [tex] \vec{F} = -k\vec{r} = -\nabla V [/tex](say)
then [tex] V = \frac{1}{2} k (r^2 + z^2) = \frac{1}{2} k (r^2 + z^2) = \frac{1}{2} k (r^2 + a^2 \phi_{0}^2) [/tex]
[tex] L = T - V = \frac{1}{2} m\dot{r}^2- \frac{1}{2} k (r^2 + a^2 \phi_{0}^2) [/tex]
is this formulation correct?
Or am i totally off?
You are totally off.
1. For a helix in cylindrical coords, z and phi vary but r is constant.
2. I don't know what "a force which depends on the distance from the center only" means. Does "center" mean the axis of the helix or does it mean the origin of coordinates?
(I assume gravity is not acting.)
3. The statement "a force which depends on the distance from the center only" does not mean that F=-kr. It just means that F depends only the magnitude of the distance from whatever "center" means.
4. After you have written down the Lagrangian, eliminate phi and z in terms of s.
 
  • #4
well our prof told us to assume that F = -kr maybe i shouldve stated taht anyway
s is the disatnce along the helix...
would this have something to do with arc length?
something along the lines of this
[tex] s = \int_{t_{1}}^{t_{2}} \sqrt{(\frac{\partial f}{\partial r})^2 + (\frac{\partial f}{\partial r})^2 + (\frac{\partial f}{\partial r})^2} [/tex]
where f is the function of the length of hte arc...?
 
Last edited:
  • #5
If s is the length along the helix, it probably is
[tex]s=\phi\sqrt{a^2+z^2}=[/tex],
with [tex]z=sa/\sqrt{r^2+a^2}[\tex]
and [tex]\phi=s/\sqrt{r^2+a^2}[\tex]
The r in F=-kr must be the distance from one point on the axis.
(Is it?)
Otherwise the force could never do anything.
 

1. What is Lagrangian mechanics?

Lagrangian mechanics is a mathematical framework used to study the motion of a system of particles or objects. It is based on the principle of least action, which states that the actual motion of a system is the one that minimizes the action, a quantity that represents the total energy of the system.

2. What is a bead of mass in Lagrangian mechanics?

A bead of mass in Lagrangian mechanics refers to a particle with a specific mass that is considered as a point of interest in a system. It can represent a physical object such as a bead on a wire or a small mass attached to a spring.

3. How is the Lagrangian of a bead of mass calculated?

The Lagrangian of a bead of mass is calculated by taking the difference between the kinetic and potential energies of the particle. The kinetic energy is given by the mass of the particle multiplied by its velocity squared, while the potential energy is determined by the forces acting on the particle and its position in the system.

4. What is the significance of studying Lagrangian mechanics of a bead of mass?

Studying the Lagrangian mechanics of a bead of mass allows us to understand and predict the motion of the particle in a given system. This framework is particularly useful in systems with complex forces or constraints, where traditional Newtonian mechanics may be difficult to apply.

5. Can Lagrangian mechanics be applied to systems with multiple beads of mass?

Yes, Lagrangian mechanics can be applied to systems with multiple beads of mass. The Lagrangian of each bead is calculated separately and then combined to obtain the overall Lagrangian of the system. This approach allows for the analysis of complex systems with multiple interacting particles.

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