Image Formed by Diverging Lens

[sapiental]

Homework Statement

2. An object is placed two focal lengths from a
diverging lens.
What type of image forms?
What is the magnification?
Where is the image?

Homework Equations

1/f = (n-1)(1/r1-1/r2)

The Attempt at a Solution

a) Virtual Image

b) m = 1

c) the image is on the same side as the object with d_i = -2f

 

[Doc Al]

Homework Equations

1/f = (n-1)(1/r1-1/r2)

That's the "Lens Maker's formula"; what you need is the "Thin Lens formula". (Look it up!)

 

[m2003]

Dear student,

Thank you for your interest in optics and for providing this question. The type of image formed by a diverging lens when an object is placed two focal lengths away is a virtual image. This means that the rays of light do not actually converge to a point, but appear to diverge from a point behind the lens. The magnification in this case would be 1, meaning that the image would be the same size as the object. This can be calculated using the formula 1/f = (n-1)(1/r1-1/r2), where f is the focal length of the lens and n is the refractive index of the medium the lens is in. Since the object is placed 2 focal lengths away, the image would also be 2 focal lengths away on the same side as the object. This can be represented as d_i = -2f, where d_i is the image distance. I hope this helps with your homework and good luck with your studies!

Best regards,

Scientist specializing in optics